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irinina [24]
3 years ago
13

Commercial grade HCl solutions are typically 39.0% (by mass) HCl in water. Determine the molality of the HCl, if the solution ha

s a density of 1.20 g/mL
Chemistry
1 answer:
marta [7]3 years ago
8 0

Molality of the solution is defined as the number of moles of a substance dissolved divided by the mass of the solvent:

Molality = number of moles / solvent mass

From the concentration of 39% (by mass) of HCl in water, we construct the following  reasoning:

in 100 g solution we have 39 g hydrochloric acid (HCl)

number of moles  = mass / molecular weight

number of moles of HCl = 39 / 36.5 = 1.07 moles

solvent (water) mass = solution mass - hydrochloric acid mass

solvent (water) mass = 100 - 39 = 61 g

Now we can determine the molality:

molality = 1.07 moles / 61 g = 0.018

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3 years ago
35.5 moles of lithium fluoride is dissolved in 65 L of solution
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Answer:

Explanation:

L

=

1.10

L

of solution

Explanation:

The Molarity

M

is calculated by the equation comparing moles of solute to liters of solution

M

=

m

o

l

L

For this question we are given the Molarity 0.88M

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25.2

g

r

a

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s

x

1

m

o

l

25.94

g

r

a

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s

=

0.97

moles

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M

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m

o

l

L

M

L

=

m

o

l

L

=

m

o

l

M

L

=

0.97

m

o

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0.88

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L

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1.10

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