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irinina [24]
3 years ago
13

Commercial grade HCl solutions are typically 39.0% (by mass) HCl in water. Determine the molality of the HCl, if the solution ha

s a density of 1.20 g/mL
Chemistry
1 answer:
marta [7]3 years ago
8 0

Molality of the solution is defined as the number of moles of a substance dissolved divided by the mass of the solvent:

Molality = number of moles / solvent mass

From the concentration of 39% (by mass) of HCl in water, we construct the following  reasoning:

in 100 g solution we have 39 g hydrochloric acid (HCl)

number of moles  = mass / molecular weight

number of moles of HCl = 39 / 36.5 = 1.07 moles

solvent (water) mass = solution mass - hydrochloric acid mass

solvent (water) mass = 100 - 39 = 61 g

Now we can determine the molality:

molality = 1.07 moles / 61 g = 0.018

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Mass of the steel is 1004.4 g

  • density of a substance can be regarded as the ratio of the mass of that substance to that of it's volume.

  • Mass of substance can be regarded as the quantitative measure of inertia, it can be simply explained as a fundamental property of all matter

<em> We can express this mathematically as ;</em>

  • Density=  \frac{ mass  }{volume  }

Given :

Density of this steel= 8.1g/cm3

Mass=  124 cm^{3}

If we make Mass subject of formula,

Mass= ( density *volume)

Then let us substitute the values into the expression

Mass= (124*8.1)

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Therefore, mass of the steel is 1004.4 g

Learn more at: brainly.com/question/9196460?referrer=searchResults

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3 years ago
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Answer: Option (b) is the correct answer.

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