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GrogVix [38]
3 years ago
12

What is the resulting pressure when you transfer gas from cylinder with a temperature of 22°C and the pressure of four atm into

a container with a temperature of 65°C? Assume volume remains constant.
Chemistry
1 answer:
Hatshy [7]3 years ago
4 0
Answer:
             P₂  =  4.58 atm

Solution:
               According to <span>Gay-Lussac's law ," the pressure of a given mass of an ideal gas at constant volume is directly proportional to absolute temperature".
For initial and final states of a gas, the relation is given as,

                                           P</span>₁ / T₁  =  P₂ / T₂   ----- (1)

Data Given;
                   P₁  =  4 atm

                   T₁  =  22 °C + 273  =  295 K

                   P₂  =  ??

                   T₂  =  65 °C + 273  =  338 K

Now, solving equation 1 for P₂,

                  P₂  =  P₁ T₂ / T₁

Putting values,

                  P₂  =  (4 atm × 338 K) ÷ 295 K

                  P₂  =  4.58 atm
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