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butalik [34]
3 years ago
14

Please answer this please don't answer if you don't know it thank you D.look at the picture​

Chemistry
1 answer:
Lina20 [59]3 years ago
3 0

Answer:

B.

Explanation:

The complementary strand always has the opposite base that connects for example; the opposite of A is T.

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a serving of a particular fruit dessert contains 20.0 g of sugar. if all the sugar is sucrose, c12h22o11, how many molecules of
Harrizon [31]

Taking into account the definition of Avogadro's number and molar mass, 3.49334×10²² molecules of sucrose are present.

<h3>Definition of molar mass</h3>

The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.

<h3>Avogadro's Number</h3>

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.

<h3>Molecules of sugar in this case</h3>

In first place, the molar mass of sucrose is 342 g/mole. So, you can apply the following rule of three: If by definition of molar mass 342 grams of the compound are contained in 1 mole, 20 grams of the compound are contained in how many moles?

amount of moles=\frac{20 gramsx1 mole}{342 grams}

<u><em>amount of moles= 0.058 moles</em></u>

Now, considering the Avogadro's number, you can apply the following rule of three: If 1 mole of the compound contains 6.023×10²³ molecules, 0.058 moles contains how many molecules?

amount of moleculas= (6.023×10²³ molecules × 0.058 moles)÷ 1 mole

<u><em>amount of molecules= 3.49334×10²² molecules</em></u>

Finally, 3.49334×10²² molecules of sucrose are present.

Learn more about

molar mass:

brainly.com/question/5216907

brainly.com/question/11209783

brainly.com/question/7132033

brainly.com/question/17249726

Avogadro's Number:

brainly.com/question/11907018

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#SPJ12

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