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maksim [4K]
1 year ago
5

A+common+iv+solution+is+0.9%+saline+(nacl+solution).+what+is+the+osmolarity+of+0.9%+saline+mosmoles/l?+the+molecular+weight+of+n

acl+is+58.44+g/mole.+pay+attention+to+the+units+that+are+asked+for+here!
Chemistry
1 answer:
Vedmedyk [2.9K]1 year ago
8 0

An osmolarity of saline solution is 308 mosmol/L.

m(NaCl) = 9 g; the mass of sodium chloride

V(solution) = 1 L; the volume of the saline solution

n(NaCl) = 9 g ÷ 58.44 g/mol

n(NaCl) = 0.155 mol; the amount of sodium chloride

number of ions = 2

Osmotic concentration (osmolarity) is a measure of how many osmoles of particles of solute it contains per liter.

The osmolarity = n(NaCl) ÷ V(solution)  × 2

The osmolarity = 0.154 mol ÷ 1 L × 2

The osmolarity = 0.154 mol/L × 1000 mmol/m × 2

The osmolarity of the saline solution = 308 mosm/L.

More about osmolarity: brainly.com/question/13258879

#SPJ4

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Answer:

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Explanation:

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Actual yield of Li3N = 5.85 grams

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Molar mass of N2 = 28 g/mol

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Step 2: The balanced equation:

6Li(s) + N2(g) → 2Li3N(s)

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Moles Li = mass Li / Molar mass Li

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Moles Li = 1.83 moles

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Moles N2 = 1.24 moles

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Mass Li3N = 0.610 moles * 34.83 g/mol

Mass Li3N = 21.2463 grams = Theoretical yield

Step 8: Calculate % yield

% yield = actual yield / theoretical yield

% yield = (5.85 / 21.2463)*100% = 27.5%

The % yield of the reaction = 27.5 %

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