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Mashcka [7]
3 years ago
9

Although Rutherford is credited with the famous gold foil scattering experiment, he didn’t actually conduct this experiment hims

elf. It was done by two of his assistants, Hans Geiger and Ernest Marsden. Do you think it was fair to name the experiment after Rutherford while ignoring the other two scientists? Why or why not?
Chemistry
1 answer:
DerKrebs [107]3 years ago
3 0
If he was the primary scientist doing it as he did alot of the heavy lifting then yes its ok, but i also think how the others should also me at least mentioned. Or they could just not name the experiment by a person just so its not too biased
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Natasha_Volkova [10]
You have to read the passage and compare and contrast the story
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3 years ago
3) which is an example of a physical change? a) grinding pepper b)toasting bread c)lighting up a grill d) baking a cake
anygoal [31]
<span>3) which is an example of a physical change

</span><span>a) grinding pepper</span>
4 0
3 years ago
Calculate the pH of a solution prepared by dissolving 0.370 mol of formic acid (HCO2H) and 0.230 mol of sodium formate (NaCO2H)
Veronika [31]

The question is incomplete, here is the complete question:

Calculate the pH of a solution prepared by dissolving 0.370 mol of formic acid (HCO₂H) and 0.230 mol of sodium formate (NaCO₂H) in water sufficient to yield 1.00 L of solution. The Ka of formic acid is 1.77 × 10⁻⁴

a) 2.099

b) 10.463

c) 3.546

d) 2.307

e) 3.952

<u>Answer:</u> The pH of the solution is 3.546

<u>Explanation:</u>

We are given:

Moles of formic acid = 0.370 moles

Moles of sodium formate = 0.230 moles

Volume of solution = 1 L

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:  

pH=pK_a+\log(\frac{[salt]}{[acid]})

pH=pK_a+\log(\frac{[HCOONa]}{[HCOOH]})

pK_a = negative logarithm of acid dissociation constant of formic acid = 3.75

[HCOONa]=\frac{0.230}{1}  

[HCOOH]=\frac{0.370}{1}

pH = ?  

Putting values in above equation, we get:  

pH=3.75+\log(\frac{0.23/1}{0.37/1})\\\\pH=3.54

Hence, the pH of the solution is 3.546

5 0
3 years ago
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On the Brønsted–Lowry concept, an acid is a substance that donates a proton (which is basically an H⁺ ion) in a solvent, and a base is a substance that accepts a proton in a solvent.

On the Lewis concept, an acid is a substance that accepts an electron pair in a solvent, and a base is a substance that donates an electron pair in a solvent.

The concepts become progressively broader, i.e., the Arrhenius concept is the most restrictive and the Lewis concept is the least restrictive. As a corollary, an Arrhenius acid or base is also both a Brønsted–Lowry acid or base and a Lewis acid or base, respectively; a Brønsted–Lowry acid or base is not necessarily an Arrhenius acid or base, but an Arrhenius acid or base is also a Lewis acid or base, respectively. And finally, a Lewis acid or base may not necessarily be either an Arrhenius or a Brønsted–Lowry acid or base.

So, with the above concepts in mind, we can match the statements in column A with the type of acid or base in column B:

\begin{center}\begin{tabular}{ c c } 1 & Bronsted Lowry acid \\  2 & Bronsted Lowry base \\   3 & Arrhenius acid \\ 4 & Arrhenius base \\ 5 & Lewis base \\ 6 & Lewis acid\end{tabular}\end{center}

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fgiga [73]

Answer:

p orbitals

Explanation:

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