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3 years ago

Which type of graph is best used to show the percentage of reactant molecules that collide during a reaction?

2 answers:

7 0

A circle graph, or a pie chart or graph, would be the type of graph that is best used when showing the percentage of reactant molecules that collide during a reaction in a graphical representation. In addition, the circle graph mainly consists of a circle being divided into parts proportional to the whole.

skelet666 [1.2K]3 years ago

6 0

Answer:

Circle Graph

Explanation:

A scatter plot shows distribution of some numbers or properties versus another property. So it should be used for analysis of distribution or probability of something.

Stem and leaf plot are used when we have to show splitting of a stem ( a number) into leaves (another numbers).

So for percentage of reactant molecules colliding cannot be represented by scatter plot or stem and leaf plot.

In a circle graph or pie chart, we divide a circle (considering it to be 100%) into different parts based on fraction or percentage of each component.

For percentage of reactant molecule, we can divide the whole circle into two parts. One part showing the percentage of non reacting molecules and other part showing the percentage of reactant molecules undergoing collision.

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Suppose you need to prepare 136.9 mL of a 0.315 M aqueous solution of NaCl.

Varvara68 [4.7K]

Answer:

2.52 g NaCl

Explanation:

(Step 1)

To find the mass, you first need to find the moles NaCl. This value can be found using the molarity ratio:

Molarity = moles / volume (L)

After you convert mL to L, you can plug the given values into the equation and simplify to find moles.

136.9 mL / 1,000 = 0.1369 L

Molarity = moles / volume

0.315 M = moles / 0.1369 L

0.0431 = moles

(Step 2)

Now, you can use the molar mass to convert moles to grams.

Molar Mass (NaCl): 22.990 g/mol + 35.453 g/mol

Molar Mass (NaCl): 58.443 g/mol

0.0431 moles NaCl 58.443 g
------------------------------ x ------------------- = 2.52 g NaCl
1 mole

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2 years ago

Which of these is an example of a physical change?

Goryan [66]

Is it a multiple choice?

4 0

3 years ago

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Calculate the standard heat of reaction for the following methane-generating reaction of methanogenic bacteria: 4CH3NH2(g) + 2H2

PIT_PIT [208]

Answer: The standard heat for the given reaction is -138.82 kJ

Explanation:

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H^o_{rxn}=\sum [n\times \Delta H_f_{(product)}]-\sum [n\times \Delta H_f_{(reactant)}]$

For the given chemical reaction:

$4CH_3NH_2(g)+2H_2O(l)\rightarrow 3CH_4(g)+CO_2(g)+4NH_3(g)$

The equation for the enthalpy change of the above reaction is:

$\Delta H_{rxn}=[(3\times \Delta H_f_{(CH_4(g))})+(1\times \Delta H_f_{(CO_2(g))})+(4\times \Delta H_f_{(NH_3(g))})]-[(4\times \Delta H_f_{(CH_3NH_2(g))})+(2\times \Delta H_f_{(H_2O(l))})]$

We are given:

$\Delta H_f_{(H_2O(l))}=-285.8kJ/mol\\\Delta H_f_{(NH_3(g))}=-46.1kJ/mol\\\Delta H_f_{(CH_4(g))}=-74.8kJ/mol\\\Delta H_f_{(CO_2(g))}=-393.5kJ/mol\\\Delta H_f_{(CH_3NH_2(g))}=-22.97kJ/mol$

Putting values in above equation, we get:

$\Delta H_{rxn}=[(3\times (-74.8))+(1\times (-393.5))+(4\times (-46.1))]-[(4\times (-22.97))+(2\times (-285.8))]\\\\\Delta H_{rxn}=-138.82kJ$

Hence, the standard heat for the given reaction is -138.82 kJ

3 0

3 years ago

Use Boyle’s law to complete the following:

mixas84 [53]

Answer:

The answer to your question is: 0.25 l

Explanation:

Data

P1 = 1 atm

V1 = 0.5 l

P2 =2 atm

V2 = ?

T = constant

Formula

V1P1 = V2P2

Clear V2 from the formula

V2 = V1P1/P2

Substitution

V2 = (0.5)(1)/2 substitution

= 0.25 l result

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Lelechka [254]

The unknown solution is acidic

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3 years ago

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