A capacitor with plates separated by distance d is charged to a potential difference ΔVC. All wires and batteries are disconnect
ed, then the two plates are pulled apart (with insulated handles) to a new separation of distance 2d. Part A Does the capacitor charge Q change as the separation increases? If so, by what factor? If not, why not?
2 answers:
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The time after being ejected is the boulder moving at a speed 20.7 m/s upward is 2.0204 s.
<h3>What is the time after being ejected is the boulder moving at a speed 20.7 m/s upward?</h3>
The motion of the boulder is a uniformly accelerated motion, with constant acceleration
a = g = -9.8
downward (acceleration due to gravity).
By using Suvat equation:
v = u + at
where: v is the velocity at time t
u = 40.0 m/s is the initial velocity
a = g = -9.8 is the acceleration
To find the time t at which the velocity is v = 20.7 m/s
Therefore,
The time after being ejected is the boulder moving at a speed 20.7 m/s upward is 2.0204 s.
The complete question is:
A large boulder is ejected vertically upward from a volcano with an initial speed of 40.0 m/s. Ignore air resistance. At what time after being ejected is the boulder moving at 20.7 m/s upward?
To learn more about uniformly accelerated motion refer to:
#SPJ4
Answer:
0.29713 m/s
Explanation:
m = Mass of person
g = Acceleration due to gravity = 9.81 m/s²
v = Velocity
r = Radius = 18 mm
By balancing the forces in the system we have
The velocity of the coaster is 0.29713 m/s
Answer:
v = 45.37 m/s
Explanation:
Given,
angle of inclination = 8.0°
Vertical height, H = 105 m
Initial K.E. = 0 J
Initial P.E. = m g H
Final PE = 0 J
Final KE =
Using Conservation of energy
v = 45.37 m/s
Hence, speed of the skier at the bottom is equal to v = 45.37 m/s