Answer:
m/s
Explanation:
Assumption: bullet leaves the muzzle at a speed of V m/s
and velocity of push received by the man be v m/s
According to newton's third law to every action there is always an equal and opposite reaction.
therefore,
mass of man× velocity = mass of bullet×its velocity
⇒70×v= 10×10^-3 ×V
solving the above eqaution we get
therefore
m/s
Answer:
v = 2 cm/s
Explanation:
The equation of the wave is
y(x,t) = (2.0cm)*cos(2π*x−4π*t)
Where,
x is measured in cm
t in s
A more general formula for this equation would be
y(x,t) = A*cos(k*x−ω*t)
Where,
A = amplitude.
k = the wavenumber
ω = the angular frequency
The velocity of the wave corresponds to
v = ω/k
v = 4π / 2π = 2 cm/s
v = 2 cm/s
The time taken for the arrow to hit the ground is 0.53 s.
The horizontal distance traveled by the arrow is 25.97 m.
The given parameters:
- Initial horizontal velocity,
= 49 m/s - Initial vertical velocity,
= 0
<h3>What is time of motion?</h3>
- This is the time taken for a projectile to land on the plane of projection.
The time of motion is calculated as follows;

The horizontal distance traveled by the arrow is calculated as follows;

Learn more about time of motion here: brainly.com/question/2364404
Answer:
The speed of the 1 kg red ball 8.04 m/s .
Explanation:
Given :
Separation between rods , d = 1.5 m .
Mass of the red ball is 1 kg .
Mass of the orange ball is 5.7 kg .
Angular velocity ,
.
Now , distance of center of mass from red ball is :

We know , speed is given by :

Hence , this is the required solution .
It itself to increased or decrease to total momentum at any moment it will be same.