A capacitor with plates separated by distance d is charged to a potential difference ΔVC. All wires and batteries are disconnect
ed, then the two plates are pulled apart (with insulated handles) to a new separation of distance 2d. Part A Does the capacitor charge Q change as the separation increases? If so, by what factor? If not, why not?
2 answers:
You might be interested in
Answer:
4.2s
Explanation:
Given parameters:
Power = 2190W
Mass of box = 1.47 x 10⁴g
distance = 6.34 x 10⁴mm
Unknown:
Time = ?
Solution:
Power is the rate at which work is done;
Mathematically;
Power =
Time =
Work done = weight x height
convert mass to kg;
100g = 1kg;
1.47 x 10⁴g = 14.7kg
convert the height to m;
1000mm = 1m
6.34 x 10⁴mm gives 63.4m
Work done = 14.7 x 9.8 x 63.4 = 9133.4J
Time taken = = 4.2s
Answer:
Explanation:
let be the mass attached, let
be the spring constant and let
be the positive damping constant.
-By Newton's second law:
where is the displacement from equilibrium position. The equation can be transformed into:
shich is the equation of motion.