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scoray [572]
3 years ago
13

A capacitor with plates separated by distance d is charged to a potential difference ΔVC. All wires and batteries are disconnect

ed, then the two plates are pulled apart (with insulated handles) to a new separation of distance 2d. Part A Does the capacitor charge Q change as the separation increases? If so, by what factor? If not, why not?

Physics
2 answers:
nevsk [136]3 years ago
8 0

Answer:

When the separation between the capacitor plates is increased to 2d, and if the battery is disconnected, the charge between the condenser plates does not change, it is the same, and this is represented by the following expression: Q'= Q

Explanation:

fgiga [73]3 years ago
5 0

Answer:

Yes, the capacitor's Q load varies inversely proportional to the distance between plates.

Explanation:

In the attached files you see the inverse relationship between capacity and distance between plates "d".

In the following formula we see its relationship with the "Q" load

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In principle, when you fire a rifle, the recoil should push you backward. How big a push will it give? Let's find out by doing a
MaRussiya [10]

Answer:

v= \frac{10\times10^{-3} V}{70} m/s

Explanation:

Assumption: bullet leaves the muzzle at a speed of V m/s

and velocity of push received by the man be v m/s

According to newton's third law to every action there is always an equal and opposite reaction.

therefore,

mass of man× velocity = mass of bullet×its velocity

⇒70×v= 10×10^-3 ×V

solving the above eqaution we get

therefore v= \frac{10\times10^{-3} V}{70} m/s

7 0
3 years ago
A traveling wave has displacement given by y(x,t)=(2.0cm)×cos(2πx−4πt), where x is measured in cm and t in s. what is the speed
quester [9]

Answer:

v = 2 cm/s

Explanation:

The equation of the wave is

y(x,t)   =  (2.0cm)*cos(2π*x−4π*t)

Where,

x is measured in cm

t in s

A more general formula for this equation would be

y(x,t)   =  A*cos(k*x−ω*t)

Where,

A = amplitude.

k = the wavenumber

ω = the angular frequency

The velocity of the wave corresponds to

v = ω/k

v = 4π / 2π = 2 cm/s

v = 2 cm/s

8 0
3 years ago
An arrow is shot parallel to horizontal from a height of 1.4 meters. It has a velocity of 49 m/s.
Mkey [24]

The time taken for the arrow to hit the ground is 0.53 s.

The horizontal distance traveled by the arrow is 25.97 m.

The given parameters:

  • Initial horizontal velocity, v_x = 49 m/s
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<h3>What is time of motion?</h3>
  • This is the time taken for a projectile to land on the plane of projection.

The time of motion is calculated as follows;

h = v_yt + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 1.4}{9.8} }\\\\t = 0.53 \ s

The horizontal distance traveled by the arrow is calculated as follows;

X = v_x t\\\\X = (49\ m/s) \times (0.53 \ s)\\\\X = 25.97 \ m

Learn more about time of motion here: brainly.com/question/2364404

5 0
2 years ago
A larger object is made of two balls separated by a massless rigid rod that is 1.5 m long. The mass of the red ball at one end i
lions [1.4K]

Answer:

The speed of the 1 kg red ball 8.04 m/s .

Explanation:

Given :

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Mass of the red ball is 1 kg .

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Angular velocity , \omega=1\ rev/s = 2\pi\ rad/s .

Now , distance of center of mass  from red ball is :

r =\dfrac{0\times 1+1.5\times 5.7}{1+5.7}\\\\r = 1.28\ m

We know , speed is given by :

v=\omega r\\\\v=2 \times \pi \times  1.28\\\\v=8.04\ m/s

Hence , this is the required solution .

5 0
3 years ago
Mass affects/does not affect the conservation of energy?
yulyashka [42]
It itself to increased or decrease to total momentum at any moment it will be same.
5 0
3 years ago
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