A capacitor with plates separated by distance d is charged to a potential difference ΔVC. All wires and batteries are disconnect
ed, then the two plates are pulled apart (with insulated handles) to a new separation of distance 2d. Part A Does the capacitor charge Q change as the separation increases? If so, by what factor? If not, why not?
2 answers:
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Answer:
Explanation:
Hi there,
To get started, recall the kinematic equations from either a textbook, equation sheet, etc. Kinematic equations are used when acceleration is <em>constant,</em> as stated in the prompt.
Best way to use kinematic equations is to see which variable you are looking for, then which variable is unknown to you and is not needed for that equation.
a) average velocity
Takes the form of:
this is the literal definition of average velocity; initial plus final divided by 2.
We know total displacement and total time elapsed, so we will use the middle form of the equation:
b) the final velocity
We can still use the average velocity formula, as the other two equations that include final velocity have acceleration variable which is unknown as of now.
Solve for final velocity:
this makes sense, since a velocity later in time is higher than a velocity earlier in time. It is increasing with increasing time because of acceleration.
c) the acceleration
There are two equations that can be used to solve this, but we will use the less time-consuming one, but both produce same answer:
Notice, change in velocity over change in time, and acceleration is constant. When acceleration is constant, it models a linear function, and acc. is just slope!
Study well and persevere. If you liked this solution, hit Thanks or give a rating!
thanks,
Answer:
Approximately .
Assumption: the ball dropped with no initial velocity, and that the air resistance on this ball is negligible.
Explanation:
Assume the air resistance on the ball is negligible. Because of gravity, the ball should accelerate downwards at a constant near the surface of the earth.
For an object that is accelerating constantly,
,
where
is the initial velocity of the object,
is the final velocity of the object.
is its acceleration, and
is its displacement.
In this case, is the same as the change in the ball's height:
. By assumption, this ball was dropped with no initial velocity. As a result,
. Since the ball is accelerating due to gravity,
.
.
In this case, would be the velocity of the ball just before it hits the ground. Solve for
.
.