The weight of the load is (mass) x (gravity)
= (350 kg) x (9.8 m/s²)
= 3,430 newtons .
The force on the surface of the liquid is the weight of the piston and its load.
The pressure on the surface of the liquid is (force) / (area)
= (3,430 newtons) / (1 m²)
= 3,430 pascals
= 3.43 kPa
This doesn't include anything for the weight of the piston without its load,
but it's certainly the closest of the choices.
Answer:
The work done will be
Explanation:
The work equation is given by:
Where:
F is the force due to gravity (weight = mg)
x is the length of the ramp (3 m)
Now, the force acting here is the component of weight in the ramp direction, so it will be:
Therefore, the work done will be:
I hope it helps you!
1. The magnitude of the gravitational force between the Earth and an m is 54.1 N.
2. The magnitude of the gravitational force between the Moon and an m is 1.91 x 10⁻⁴ N.
3. The ratio of the magnitude of the gravitational force between an m on the surface of the Earth due to the Sun to that due to the Moon is 169.6.
<h3>
Gravitational force between Earth and mass, m</h3>
The gravitational force between Earth and mass, m is calculated as follows;
F(Earth) = Gm₁m₂/R²
F(Earth) = (6.67 x 10⁻¹¹ x 5.5 x 5.98 x 10²⁴)/(6,370,000)²
F(Earth) = 54.1 N
<h3>
Gravitational force between Moon and mass, m</h3>
F(moon) = Gm₁m₂/R²
F(moon) = (6.67 x 10⁻¹¹ x 5.5 x 7.36x 10²²)/(3.76 x 10⁸)²
F(moon) = 1.91 x 10⁻⁴ N
<h3>
Gravitational force between Sun and mass, m</h3>
F(sun) = Gm₁m₂/R²
F(sun) = (6.67 x 10⁻¹¹ x 5.5 x 1.99x 10³⁰)/(1.5 x 10¹¹)²
F(sun) = 0.0324 N
<h3>Ratio of F(sun) to F(moon)</h3>
= 0.0324/1.91 x 10⁻⁴
= 169.6
Thus, the magnitude of the gravitational force between the Earth and an m is 54.1 N.
The magnitude of the gravitational force between the Moon and an m is 1.91 x 10⁻⁴ N.
The ratio of the magnitude of the gravitational force between an m on the surface of the Earth due to the Sun to that due to the Moon is 169.6.
Learn more about gravitational force here: brainly.com/question/72250
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Answer:
Levi did not apply any fertilizer to one of his plants..
Explanation:
In an experiment, there are two major groups namely: control group and experimental group. Control group is the group in an experiment that does not receive the experimental treatment i.e. the group which the independent variable is not applied to.
In this case, Levi is trying to examine the effect of fertilizer on the growth of tomato plants where he used varying amounts of fertilizer on three of the four plants he used for the experiment. The fourth plant did not receive any amount of fertilizer, which is the independent variable (variable being manipulated or changed). This means that Levi prepared the control group in his experiment by NOT APPLYING ANY FERTILIZER TO ONE OF HIS PLANTS.