We could determine the acceleration using this formula

Given from the question v₀ = 23 m/s, v₁ = 0 (the car stops), t = 5 s
plug in the numbers



a = -4.6
The acceleration is -4.6 m/s²
Answer:
Explanation:
<h2><u>Given</u> :-</h2>
<h2><u>To Find</u> :-</h2>
<h2><u>Formula to be used</u> :-</h2>
Where,
- K.E. = Kinetic energy possessed by the body
- M = Mass of the body
- V = Velocity of the body
<h2><u>Solution</u> :-</h2>








- Velocity of the vehicle at the instant is

<em>Answer:</em>
<em>The answers are: </em>
- <em>A-which is the image is always right side up.</em>
- <em>E-the image is virtual</em>
<em></em>
<em>Explanation: MY EXPLANATION IS YOU ARE WELCOME BIG DOG 100..</em>
<em></em>
<h2 />
For the answer to the question above, so at the instant, the acceleration of the airplane is southward, the direction of the velocity is also southward. The direction should be the same because it is both a vector quantity and it does not make sense if the direction and acceleration have different direction.
<span>Mirage is due to (A). unequal heating of different parts of the atmosphere,
because that produces unequal density of different parts of the atmosphere,
which bends the light.
</span>