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GenaCL600 [577]
3 years ago
15

Select the correct answer.

Physics
1 answer:
lawyer [7]3 years ago
5 0

I believe the answer is C

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True or false: Displacement is the total path traveled by an object
amm1812

Answer:true

Explanation:

Displacement is the vector representation of a change in position. It is path independent and is equivalent to the straight line distance between the start and end locations. Distance is a scalar quantity that reflects the path traveled.

5 0
3 years ago
A ray of light is projected into a glass tube that is surrounded by air. The glass has an index of refraction of 1.50 and air ha
Tamiku [17]

Answer:

θ = 41.8º

Explanation:

This is an internal total reflection exercise, the equation that describes this process is

         sin θ = n₂ / n₁

where n₂ is the index of the incident medium and n₁ the other medium must be met n₁> n₂

        θ = sin⁻¹ n₂ / n₁

let's calculate

       θ = sin⁻¹ (1.00 / 1.50)

       θ = 41.8º

4 0
3 years ago
At an instant when the displacement is equal to a/2, what fraction of the total energy of the system is potential?
madreJ [45]
<span>At an instant when the displacement is equal to a/2, Potential energy U = 1/2ka(square) where a is displacement. when a= a/2 U = 1/4ka(square) U = E/4 Potential Energy = 1/4 Total energy</span>
4 0
3 years ago
If you could help me out that would be fantastic.?!!!
Volgvan
It's either C. Or B.
3 0
3 years ago
a chamber with a fixed volume of 1.0 meters cubed contains a monatomic gas at 3.00 *10^K. The chamber is heated to a temperature
igomit [66]

Answer:

Explanation:

Given

Volume of fixed chamber V=1 m^3

Initial Temperature T_1=300 K

Final Temperature T_2=400 K

Heat Supplied Q=10 J

From First law of thermodynamics

Change in internal energy of the system is equal to heat added minus work done by the system

\Delta U=Q-W

as the volume is fixed therefore work

W=\int PdV=0

thus \Delta U=mc_v\Delta T=Q

c_v for mono-atomic gas is 12.471 J/K-mol

n\times 12.471\times (400-300)=10

n=0.008018 mol

and 1 mole contains 6.022\times 10^{23} molecules

thus  No of molecules=0.008018\times 6.022\times 10^{23}

No of molecules=4.82\times 10^{21} molecules

3 0
3 years ago
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