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kenny6666 [7]
3 years ago
7

How is heavy water different from natural water

Chemistry
2 answers:
ryzh [129]3 years ago
6 0
Photosynthesis and how global warming affects it
Sergeu [11.5K]3 years ago
5 0

Answer:

Instead of normal protium atoms, heavy water consists of two deuterium atoms. Like normal water, heavy water is an odorless liquid at room temperature. Moreover, deuterium, tantamount to protium, is also a stable isotope. This ensures that heavy water is not radioactive

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Calculate the mean rate of reaction when 23 cm<br> of gas<br> is produced in 15 seconds.
katrin2010 [14]

Answer:

1.53 cm/s

Explanation:

Rate = Length/time

        = 23/15

        = 1.53 cm/s

<u>BRAINLIEST?</u>

<u>PRETTY SURE IT IS.</u>

3 0
2 years ago
The recommended daily intake of potassium ( K ) is 4.725 g . The average raisin contains 3.513 mg K . Fill in the denominators o
kondor19780726 [428]

Explanation:

It is known that 1 gram contains 1000 milligrams. And, mathematically we can represent it as follows.

             \frac{1 g}{1000 mg} or \frac{1000 mg}{1 g}

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4 0
3 years ago
Please answer this.A) ____ N2 + ____ H2 → ____ NH3B) ____ KClO3 → ____ KCl + ____ O2C) ____ NaCl + ____ F2 → ____ NaF + ____ Cl2
Lady_Fox [76]

1) Decomposition reactions. In this type of reaction, a compound is broken down into simpler compounds.

AB\rightarrow A+B

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Read 2 more answers
What volume of o2 is needed to react fully with 720. Ml of nh3
Galina-37 [17]

Ammonia undergoes combustion with oxygen to produce nitric oxide and water. The volume of the oxygen required to react with 720 ml of ammonia is 900 ml.

<h3>What is volume?</h3>

Volume is the area occupied by the substance and is the ratio of the mass to the density.

At STP, 1 mole of gas occupies 22.4 L of volume

Given,

Volume of ammonia reacted = 0.720 L

The combustion reaction is shown as,

\rm 4NH_{3} + 5O_{2} \rightarrow 4NO +6H_{2}O

From the stoichiometry of the reaction, it can be said that,

(4 \times  22.4) L of ammonia reacts with (5 \times  22.4) L of oxygen gas.

So, 0.720 L of  ammonia will react with:

\dfrac{ (5 \times  22.4)}{(4 \times  22.4)} \times 0.720 = 0.9 \;\rm L

Therefore, the volume of oxygen required is 900 mL.

Learn more about volume here:

brainly.com/question/14090111

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2 years ago
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