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alekssr [168]
3 years ago
11

Is it true that soaps are salts of sulfonic acids though some have been made from alkyl sulphonates​

Chemistry
1 answer:
Neko [114]3 years ago
3 0

Answer:

It is false.

Soaps are sodium and potassium salts of fatty acids.

Synthetic detergents on the other hand, are salts of long-chain alkyl sulfuric  acids (sulfonic acid) or alkylbenzenesulfonic acids, rather than carboxylic acids.

Explanation:

Soaps are sodium and potassium salts of fatty acids. Soaps are made by the process of saponification in which an alkali is added to a fat or oil and then boiled to produce a salt of the fatty acid known as soap. The alkali used may be sodium or potassium hydroxide. However, the advantage of potassium soaps is that are more soluble and lather more easily.

<em>Salts of sulfonic acids or alkylbenzenesulphonates are known as detergents</em>. Unlike soaps, they are not salts of fatty acids and are more soluble in hard water, because the polar sulfonate ion of detergents does not readily bind to calcium and other ions found in hard water. Thus, detergents are more widely used as cleansing agents than soaps

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Alpha and Beta particles can be stopped by our skin. Gamma particles cannot be stopped by our skin.
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3 years ago
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How can convection in the mantle affect the positions of Earth's continents?
Elena-2011 [213]

Answer:

Scientists believe that convection circulation within the mantle helps continents to move. As heat from Earth's innermost layer—the core—transfers to the bottom layer of mantle rock, the rock warms, softens, and rises upward. ... This churning motion in the mantle appears to be a major factor in plate movement.

Explanation:

7 0
2 years ago
A sample of the chiral molecule limonene is 79% enantiopure. what percentage of each enantiomer is present? what is the percent
Degger [83]

Answer :  The % of (+) limonene isomer = 79%


                The % of (-) limonene isomer = 0%


                The % of enantiomeric excess = 58%


Explanation :   Enantiomeric excess (ee) is the measurement of purity used for chiral substances.


Given,


% of pure limonene enantiomer = The % of (+) limonene isomer = 79%


Therefore, The % of (-) limonene isomer = 0%


Formula used :  

\%(+)\text{ isomer}=\frac{ee}{2}+50\%


Where,         ee → enantiomeric excess


Now, put all the values in above formula, we get the value of enantiomeric excess (ee).


     {ee}=\frac{\%(+)-50\%}{2}


            =\frac{79\%-50\%}{2}


              = 58%



7 0
3 years ago
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Dubnium chloride chemical formula
cupoosta [38]

Answer:

Db

Dubnium/Symbol

Explanation:

please mark my answer in brainlist plz

4 0
2 years ago
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The dissociation of sulfurous acid (H2SO3) in aqueous solution occurs as follows:
aksik [14]

Answer:

The [SO₃²⁻]

Explanation:

From the first dissociation of sulfurous acid we have:

                         H₂SO₃(aq) ⇄ H⁺(aq) + HSO₃⁻(aq)

At equilibrium:  0.50M - x          x            x

The equilibrium constant (Ka₁) is:

K_{a1} = \frac{[H^{+}] [HSO_{3}^{-}]}{[H_{2}SO_{3}]} = \frac{x\cdot x}{0.5 - x} = \frac {x^{2}}{0.5 -x}

With Ka₁= 1.5x10⁻² and solving the quadratic equation, we get the following HSO₃⁻ and H⁺ concentrations:

[HSO_{3}^{-}] = [H^{+}] = 7.94 \cdot 10^{-2}M

Similarly, from the second dissociation of sulfurous acid we have:

                              HSO₃⁻(aq) ⇄ H⁺(aq) + SO₃²⁻(aq)

At equilibrium:  7.94x10⁻²M - x          x            x

The equilibrium constant (Ka₂) is:  

K_{a2} = \frac{[H^{+}] [SO_{3}^{2-}]}{[HSO_{3}^{-}]} = \frac{x^{2}}{7.94 \cdot 10^{-2} - x}  

Using Ka₂= 6.3x10⁻⁸ and solving the quadratic equation, we get the following SO₃⁻ and H⁺ concentrations:

[SO_{3}^{2-}] = [H^{+}] = 7.07 \cdot 10^{-5}M

Therefore, the final concentrations are:

[H₂SO₃] = 0.5M - 7.94x10⁻²M = 0.42M

[HSO₃⁻] = 7.94x10⁻²M - 7.07x10⁻⁵M = 7.93x10⁻²M

[SO₃²⁻] = 7.07x10⁻⁵M

[H⁺] = 7.94x10⁻²M + 7.07x10⁻⁵M = 7.95x10⁻²M

So, the lowest concentration at equilibrium is [SO₃²⁻] = 7.07x10⁻⁵M.

I hope it helps you!

8 0
3 years ago
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