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2 years ago

What element will lose electrons to form An ion

Chemistry

1 answer:

Andreas93 [3]2 years ago

7 0

Answer:

elements which are basic in nature or we can say that it is a metal so we conclude that it will loose electron or to form an ions

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Which equation represents the combined gas law?

stealth61 [152]

Answer:

P1V1/T1= P2V2/T2

Explanation:

Combined gas law involves Boyle's law and Charles law altogether with the formula of Boyle's law as P1V1=P2V2

formula for charles law as V1/T1=V2/T2

so when combined form P1V1/T1=P2V2/T2

4 0

2 years ago

Number of moles in 31.99g O2 <br> And 176.8g NaCl

sergey [27]

#O_2

$\\ \sf\longmapsto No\:of\;moles=\dfrac{Given\:mass}{Molar\:mass}$

$\\ \sf\longmapsto No\:of\:moles=\dfrac{31.99}{32}$

$\\ \sf\longmapsto No\:of\:moles\approx 1$

#NaCl

$\\ \sf\longmapsto No\:of\:moles=\dfrac{176.8}{58.5}$

$\\ \sf\longmapsto No\;of\:moles=3mol$

8 0

1 year ago

Answer these two questions, please.

IRINA_888 [86]

Answer:

neom, sodium bicarbonate

7 0

2 years ago

5.11 g of MgSO₄ is placed into 100.0 mL of water. The water's temperature increases by 6.70°C. Calculate ∆H, in kJ/mol, for the

cupoosta [38]

Answer: Thus ∆H, in kJ/mol, for the dissolution of MgSO₄ is -66.7 kJ

Explanation:

To calculate the entalpy, we use the equation:

$q=mc\Delta T$

where,

q = heat absorbed by water = ?

m = mass of water = ${\text {volume of water}}\times {\text {density of water}}=100.0ml\times 1.00g/ml=100.0g$

c = heat capacity of water = 4.186 J/g°C

$\Delta T$ = change in temperature = $6.70^0C$

$q=100.0g\times 4.184J/g^0C\times 6.70^0C=2803.3J=2.8033kJ$

Sign convention of heat:

When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.

The heat absorbed by water will be equal to heat released by $MgSO_4$

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass = 5.11 g

Molar mass = 120 g/mol

Putting values in above equation, we get:

$\text{Moles of }MgSO_4=\frac{5.11g}{120g/mol}=0.042mol$

0.042 moles of $MgSO_4$ releases = 2.8033 kJ

1 mole of $MgSO_4$ releases = $\frac{2.8033 kJ}{0.042}\times 1=66.7kJ$

Thus ∆H, in kJ/mol, for the dissolution of MgSO₄ is -66.7 kJ

3 0

3 years ago

at its discovery, benzene was recognized to be a unique unsaturated hydrocarbon. this was because it either failed to react, or

Bingel [31]

At its discovery, benzene was recognized to be a unique unsaturated hydrocarbon because it either failed to react, by substitution with common reagents or reacted by addition that led to reactions with alkenes.

<h3>What are unsaturated hydrocarbons?</h3>

Unsaturated hydrocarbons are the hydrocarbons which have at least on double or triple carbon to carbon bond in its molecules.

All other hydrocarbons are unsaturated except for the alkanes and the cyclic alkanes.

Benzene is an aromatic compound which has a special six-carbon ring with are resonance structure reflecting the presence of three carbon-carbon bonds in its molecules.

The common reactions of unsaturated hydrocarbons are substitution and addition reactions.

However, benzene on its discovery did not undergo any of these reactions.

In conclusion, benzene showed a difference when compared with the common unsaturated hydrocarbons as it did not undergo either substitution or addition reactions.

Learn more about benzene at: brainly.com/question/6028840

#SPJ1

6 0

1 year ago