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Ludmilka [50]
3 years ago
11

What element will lose electrons to form An ion

Chemistry
1 answer:
Andreas93 [3]3 years ago
7 0

Answer:

elements which are basic in nature or we can say that it is a metal so we conclude that it will loose electron or to form an ions

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PLEASE HELP NOOWWW I WILL GIVE BRAINLIEST
Misha Larkins [42]

Answer:

c

Explanation:

5 0
3 years ago
Which term is used to describe the reactant that is used up completely and controls the amount of product that can be produced d
givi [52]

Answer: Option (c) is the correct answer.

Explanation:

A limiting reagent is defined as a reagent that completely gets consumed in a chemical reaction. A limiting reagent limits the formation of products.

For example, we have given 5 mol of A and the reaction is 2A + 4B \rightarrow 2AB

Whereas when 4 mol B will react with 2 mol of A. Hence, 8 mol of B will react with 4 mol A as follows.

                        \frac{2}{4} \times 8 = 4 mol

As, the given moles of A is more than the required moles. Thus, it is considered as an excess reagent.

Hence, B is a limiting reagent because it limits the formation of products.

Thus, we can conclude that limiting reactant is the term used to describe the reactant that is used up completely and controls the amount of product that can be produced during a chemical reaction.  

6 0
3 years ago
A 125.0 mg sample of an unknown, monoprotic acid was dissolved in 100.0 mL of distilled water and titrated with a 0.050 M soluti
Katarina [22]

Im honestly not really sure ..

i just need points

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6 0
4 years ago
How many ions can iron form
svp [43]
They can probably form 3 of them
6 0
3 years ago
1.25mole Nocl was placed in a2.50l reaction chamber at 427c. After equilibrium was reached .1.10moles of Nocl remained.Calculate
Dmitry [639]

Answer:

Kc → 5.58×10⁻⁴

Explanation:

Equilibrium reaction is:

2NOCl (g) ⇄  2NO (g) + Cl₂(g)

Initially we have 1.25 moles of NOCl

After the equilibrium, we have 1.10 moles. So, during the process:

(1.25 mol - 1.1 mol) = 0.15 moles have reacted.

As ratio are 2:2, and 2:1, 0.15 moles of NO and (0.15 /2) = 0.075 moles of chlorine, were produced in the equilibrium.

Finally in equilibrium we have: 1.10 moles of NOCl, 0.15 moles of NO and 0.075 moles of Cl₂. But these amount are not molar, so we need molar concentration in order to determine Kc:

1.10 mol /2.50L = 0.44 M

0.15 mol / /2.50L = 0.06 M

0.075 mol /2.50L = 0.03 M

Let's make expression for Kc → [Cl₂] . [NO]² / [NOCl]²

Kc = (0.03 . 0.06²) / 0.44² → 5.58×10⁻⁴

4 0
3 years ago
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