Answer:
The process can be represented as shown in the figure below; having got the diagram, we can solve for the questions.
A. the number of moles of gas used
n = PV/ RT = (1.013 *10^5 Pa) * (5.0 *10^-3 m^3) / (8.314 * 300)
n = 5.065 * 10^2 / 2494.2
n = 0.00203 *10^2
n = 0.203 moles
B. Temperature at point C (Tc)
Pa/Ta= Pb/Tb
Tb = Pb *Ta / Pa
Tb = 3 * 300 / 1
Tb = 900 K
Since Tb = Tc = 900 K
C. For process AB,
work done is zero
For process BC,
work done = -nRTbln (Vc/Vb)
W = -(0.203 * 8.314 * 900 ln (3)
W = -(1.518 kJ ln 3
W = -1.67 kJ
For process CA,
W = -P V =-nRT
W = -(0.203 * 8.314 * (-600))
W = 1.01 kJ
Explanation:
For the absorbance of the solution in a 1.00 cm cell at 500 nm is mathematically given as
A’ = 0.16138
<h3>What is the absorbance of the solution in a 1.00 cm cell at 500 nm?</h3>
Absorbance (A) 2 – log (%T) = 2 – log (15.6) = 0.8069
Generally, the equation for the Beer’s law is mathematically given as
A = ε*c*l
0.8069 = ε*c*(5.00 )
ε*c = 0.16138 cm-1
then for when ε*c is constant
l’ = 1.00
A’ = (0.16138 cm-1)*(1.00 cm)
A’ = 0.16138
In conclusion, the absorbance of the solution in a 1.00 cm cell at 500 nm is
A’ = 0.16138
Read more about Wavelength
brainly.com/question/3004869
C. Groups 13-16 contain metalloids.
If you look on a periodic table, these usually have a different color.
Answer: A golfer hitting a golf ball.
Explanation:
The atomic particles move more in this option than the others.
