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3 years ago

Which situation is best represented by the expression 2c-5 ?

Mathematics

1 answer:

Oksanka [162]3 years ago

3 0

2c-5=5 less than 2 times c

B

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How many minutes does it take a man to walk a mile if he walks at a rate of 4 feet per second

Serjik [45]

Answer:

1,320 seconds or 22 minutes to walk 1 mile

Step-by-step explanation:

5280 feet (1 mile) ÷ 4 feet per second = 1,320 seconds or 22 minutes

3 0

3 years ago

An 8.0 kg block is moving at 3.2 m/s. A net force of 10 N is constantly applied on the block in the direction of its movement, u

Softa [21]

Answer:

5.02 m/s

Step-by-step explanation:

We are given that

Mass of block,m=8 kg

Initial velocity,u=3.2 m/s

Net force ,F=10 N

Distance,s=6 m

We have to find the approximate final velocity of the block.

We know that $a=\frac{F}{m}$

Using the formula

$a=\frac{10}{8}=\frac{5}{4} m/s^2$

We know that

$v=\sqrt{u^2+2as}$

Using the formula

$v=\sqrt{(3.2)^2+2\times \frac{5}{4}\times 6}$

$v=5.02 m/s$

8 0

3 years ago

PLEASE ANSWER ITS DUE SO SOON

geniusboy [140]

the line is negative because it goes down as you move right

slope = rise/run = 4/2 = 2

y = 2x+b

use a point on the line - I picked (-4, 3)

3 = 2(-4)+b

3 = -8+b

11 = b

8 0

3 years ago

Find the product.

tankabanditka [31]

the answer would be c

8 0

3 years ago

Read 2 more answers

Find a solution x = x(t) of the equation x′ + 2x = t2 + 4t + 7 in the form of a quadratic function of t, that is, of the form x(

Temka [501]

The particular quadratic solution to the ODE is found as follows:

$x=at^2+bt+c$
$x'=2at+b$

$(2at+b)+2(at^2+bt+c)=t^2+4t+7$
$2at^2+(2a+2b)t+(b+2c)=t^2+4t+7$

$\begin{cases}2a=1\\2(a+b)=4\\b+2c=7\end{cases}\implies a=\dfrac12,b=\dfrac32,c=\dfrac{11}4$

Note that there's also the fundamental solution to account for, which is obtained from the characteristic equation for the ODE:

$x'+2x=0\implies r+2=0\implies r=-2$

so that $x_c=Ce^{-2t}$ is a characteristic solution to the ODE, and the general solution would be

$x=Ce^{-2t}+\dfrac{t^2}2+\dfrac{3t}2+\dfrac{11}4$

4 0

4 years ago