Answer:
b) 41.6 square inches
Step-by-step explanation:
A regular hexagon is inscribed in a circle with a diameter of 8 inches.
Step 1
We find the radius
Radius = Diameter/2
= 8 inches/2 = 4 inches
a. What is the perimeter of the hexagon?
b. What is the area of the hexagon?
An hexagon has 6 sides
The number of angles in an hexagon is calculated as:
[(Number of sides - 2) x 180]
= (6 - 2) x 180 = 720 ÷ 6 = 120°
The hexagon into 6 equilateral triangles with 4 for each of its sides.
The area of one of the triangles:
Height = 2√3
- one triangle's area = (1/2)bh = (1/2)(4)(2√3) = 4√3
The area of the hexagon by multiplying the one triangle's area by 6:
6 x 4√3 = 24√3 square inches
= 41.569219382 square inches
Approximately = 41.6 square inches
The discriminant is the value of b²-4ac
in this case, b=-8, a=4, c=4, so the discriminant is (-8)²-4*4*4=0
when the discriminant is 0, there is one rational solution.
when the discriminant is larger than 0, there are two rational solutions.
when the discriminant is smaller than 0, there are no real solutions. <span />
Answer:
17/80
Step-by-step explanation:
change 21 1/4 to a fraction
2125/10000 and simplfy
425/2000
85/400
17/80
f(-1) = -11 and f(3) = -3 . these functions are true .
What does a math function mean?
- A relationship between a group of inputs and one output each is referred to as a function.
- A function is an association between inputs in which each input is connected to precisely one output.
- A domain, codomain, or range exists for every function. f(x), where x is the input, is a common way to refer to a function.
- In mathematics, a function is an expression, rule, or law that establishes the relationship between two variables (the dependent variable).
given function f(x) = 2x - 9
f(-1) = -11 ⇒ x = -1 put in function
f( -1 ) = 2 * -1 - 9 ⇒ - 11
f(2) = 5 ⇒ x = 2 put in function
f( 2 ) = 2 * 5 - 9 = 1
f(3) = -3 ⇒ x = 3 put in function
f ( 3 ) = 2 * 3 - 9 = -3
f(-3) = 15 ⇒ x = -3 put in function
f( -3) = 2 * -3 - 9 = - 15
Learn more about function
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|2x - 5| - 2 = 3 |add 2 to both sides
|2x - 5| = 5 ⇔ 2x - 5 = 5 or 2x - 5 = -5 |add 5 to both sides
2x = 10 or 2x = 0 |divide both sides by 2
x = 5 or x = 0
