Remember
![x^ \frac{m}{n} = \sqrt[n]{x^m}](https://tex.z-dn.net/?f=x%5E%20%5Cfrac%7Bm%7D%7Bn%7D%20%3D%20%5Csqrt%5Bn%5D%7Bx%5Em%7D%20)
and
and
(x^m)^n=x^(mn)
so
![((7x^3)(y^2))^ \frac{2}{7} = \sqrt[7]{((7x^3)(y^2))^2}](https://tex.z-dn.net/?f=%20%28%287x%5E3%29%28y%5E2%29%29%5E%20%5Cfrac%7B2%7D%7B7%7D%20%3D%20%5Csqrt%5B7%5D%7B%28%287x%5E3%29%28y%5E2%29%29%5E2%7D%20)
=
![\sqrt[7]{((7x^3)^2(y^2)^2)}](https://tex.z-dn.net/?f=%20%5Csqrt%5B7%5D%7B%28%287x%5E3%29%5E2%28y%5E2%29%5E2%29%7D%20)
=
![\sqrt[7]{((7^2x^6)(y^4))}](https://tex.z-dn.net/?f=%20%5Csqrt%5B7%5D%7B%28%287%5E2x%5E6%29%28y%5E4%29%29%7D%20)
=
![\sqrt[7]{((49x^6)(y^4))}](https://tex.z-dn.net/?f=%20%5Csqrt%5B7%5D%7B%28%2849x%5E6%29%28y%5E4%29%29%7D%20)
=
![\sqrt[7]{49x^6y^4}](https://tex.z-dn.net/?f=%20%5Csqrt%5B7%5D%7B49x%5E6y%5E4%7D%20)
and
and
(x^m)^n=x^(mn)
so
What is 1 5/8 divided by 5 1/7
1 answer:
Answer: 91/288
Step-by-step explanation: To divide mixed numbers, first write the mixed numbers as improper fractions.
We can do this by multiplying the denominator by the whole number and then adding the numerator. Then, we put our new numerator over our old denominator.
So here, we can write 1 and 5/8 as the improper fraction 13/8 and we can write 5 and 1/7 as the improper fraction 36/7.
So here, we have 13/8 ÷ 36/7.
Dividing by a fraction is the same as multiplying by the reciprocal of that fraction.
So here, 13/8 ÷ 36/7 is the same as 13/8 × 7/36.
So now we are simply multiplying fractions and we do this by multiplying across the numerators and multiply across the denominators.
So now we have 91/288 which is in lowest terms.
This means that 1 and 5/8 divided by 5 and 1/7 is 91/288.
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