Answer:
When like charges come together, they repel each other. For instance, when the north and south poles of a magnet come together, they push each other apart. The like poles in the magnet repel each other and unlike poles attract each other much. The same reaction occurs in like and unlike charges. Also, the repulsion acts along the line between the two charges.
Density I'm not sure
volume unchanged
mass unchanged
shape- water
Answer:
The answer is B.
Explanation:
They are in control of the experiment, they can change it the variables to better help the experiment.
Answer:
6.88 m/s
Explanation:
The Conservation of Energy states that:
Initial Kinetic Energy + Initial Potential Energy = Final Kinetic Energy + Final Potential Energy
So we can write

We can cancel the common factor of
which leaves us with

Lets solve for 

Subtract
from both sides of the equation.

Multiply both sides of the equation by 2.

Simplify the left side.
Apply the distributive property.

Cancel the common factor of 2.

Take the square root of both sides of the equation to eliminate the exponent on the right side.

We are given
.
We can now solve for the final velocity.

Anything multiplied by 0 is 0.


