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blondinia [14]
3 years ago
8

An electromagnetic wave is traveling through free space. The amplitudes of the wave's electric and magnetic fields are E 0 E0 an

d B 0 B0 , respectively. The wave then passes through a filter that reduces the amplitude of the electric field by half ( E 0 / 2 ) (E0/2) . What is the amplitude of the magnetic field after the wave passes through the filter?
Physics
2 answers:
nydimaria [60]3 years ago
7 0

Answer:

B = Bo/2

Explanation:

Bo depends on Eo as stated by the relation

Bo = Eo/c

Where

Bo = magnetic field amplitude

Eo = Electric field amplitude

c = Speed of light in vacuum = constant

Since c is constant whatever happens to the electric field amplitude will also affect the magnetic field amplitude. In the same vein if the electric field amplitude is halfed, the magnetic field amplitude will also be halfed. Hence

(Bo)new = Bo/2

Sauron [17]3 years ago
5 0

Answer:

B = Bo / 2

Explanation:

Magnesium and electric fields are related in an electromagnetic wave

        E / B = c

If the electric field is halved the magnetic field must also be halved to meet the written equation

           B = Bo / 2

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You and your friend throw balloons filled with water from the roof of a several story apartment house. You simply drop a balloon
Aleks [24]

Answer:

Height = 53.361 m

Explanation:

There are two balloons being thrown down, one with initial speed (u1) = 0 and the other with initial speed (u2) = 43.12

From the given information we make the following summary

u_{1} = 0m/s

t_{1} = t

u_{2} = 43.12m/s

t_{2} = (t-2.2)s

The distance by the first balloon is

D = u_{1} t_{1}  + \frac{1}{2} at_{1}^2

where

a = 9.8m/s2

Inputting the values

D = (0)t + \frac{1}{2} (9.8)t^2\\ D = 4.9t^2

The distance traveled by the second balloon

D = u_{2} t_{2}  + \frac{1}{2} at_{2}^2

Inputting the values

D = (43.12)(t-2.2)  + \frac{1}{2} (9.8)(t-2.2)^2

simplifying

D = 4.9t^2 + 21.56t -71.148

Substituting D of the first balloon into the D of the second balloon and solving

4.9t^2 = 4.9t^2 + 21.56t -71.148 \\ 21.56t = 71.148\\ t = 3.3s

Now we know the value of t. We input this into the equation of the first balloon the to get height of the apartment

D = 4.9(3.3)^2\\ D = 53.361 m

7 0
3 years ago
Describe a situation in which you can accelerate even though your speed doesn’t change.
KATRIN_1 [288]

Acceleration is not the same as speeding up. It refers to any modification of motion's direction or speed. Accelerated motion is any movement that is not constant speed in a straight line.

<h3>What is meant by acceleration?</h3>

The rate at which an object's velocity for time changes is referred to as acceleration in mechanics. They are vector quantities and accelerations. The direction of the net force acting on an object determines the direction of its acceleration.

An object's velocity can alter depending on whether it moves faster or slower or in a different direction. A falling apple, the moon orbiting the earth, and a car stopped at a stop sign are a few instances of acceleration.

The rate at which velocity changes is called acceleration. Acceleration typically indicates a change in speed, but not necessarily. An item that follows a circular course while maintaining a constant speed is still moving forward because the direction of its motion is shifting.

To learn more about acceleration refer to:

brainly.com/question/605631

#SPJ4

6 0
1 year ago
A 4.00 kg ball is swung in a circle on the edge of a 1.50 m rope. The time it takes for the ball to complete one rotation is 3.4
lorasvet [3.4K]

Answer:

The answer is below

Explanation:

The length of the rope is equal to the radius of the circle formed by the complete rotation of the rope. Therefore the radius = 1.50 m.

a) The distance covered by the rope when completing one rotation is the same as the perimeter of the circle. Hence:

Distance covered in one rotation = 2π * radius = 2π * 1.5 = 3π meters

The velocity of the ball = Distance / time = 3π meters / 3.4 seconds = 2.77  m/s

b) The initial velocity (u) is 0 m/s, the final velocity is 2.77 m/s during time (t) = 3.4 s. Hence acceleration (a):

v = u + at

2.77 = 3.4a

a = 0.82 m/s²

c) Force on ball = mass * acceleration = 4 * 0.82 = 3.28 N

8 0
2 years ago
The spring in the muzzle of a child's spring gun has a spring constant of 730 N/m. To shoot a ball from the gun, first the sprin
Korolek [52]

Answer:

a. V=11.84 m/s

b.x=0.052m

Explanation:

a).

Given

K=730 N/m,m=0.053kg, h=1.90m.

v_f^2=v_i^2+2*g*h

v_i^2=2*g*h=2*9.8m/s^2*1.9m

v_i=\sqrt{2*9.8m/s^2*1.9m}=\sqrt{37.24 m^2/s^2}

v_i=6.1 m/s

v_i=V*sin(31)

V=\frac{v_i}{sin(31)}=\frac{6.1m/s}{sin(31)}

V=11.84 m/s

b).

K_k=\frac{1}{2}*K*x^2

No friction on the ball so:

x^2=\frac{2*K_k}{K}

x=\sqrt{\frac{2*0.053kg*9.8m/s^2*1.9m}{730N/m}}

x=\sqrt{2.7x10^{-3}m^2}=0.052m

5 0
2 years ago
a stone is thrown down off a bridge with a veloctiy of 5.6m/s. What is the velocity afer 3 seconds have passed?
Flura [38]
I think it's 16.8 because you multiply 5.6x3=16.8
6 0
3 years ago
Read 2 more answers
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