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max2010maxim [7]
2 years ago
12

Tire or false

Physics
1 answer:
spayn [35]2 years ago
8 0
1 and 4 are tire.
2 and 3 are not.
You might be interested in
Question 3 (1 point)
g100num [7]

Answer:

B) 18.5 m/

s west

Explanation:

Scalar quantity has MAGNITUDE only

Vector quantity has MAGNITUDE and DIRECTION

Hope this is correct and helpful

HAVE A GOOD DAY!

3 0
3 years ago
Dona rolls a marble with a speed of 5.0/m/s across a level table that is 1.6m above the floor. Upon reaching the edge of the tab
san4es73 [151]

Answer:

2.9 m

Explanation:

First find the time it takes to reach the floor.

y = y₀ + v₀ t + ½ at²

(0 m) = (1.6 m) + (0 m/s) t + ½ (-9.8 m/s²) t²

t = 0.571 s

Next, find the distance it travels in that time.

x = x₀ + v₀ t + ½ at²

x = (0 m) + (5.0 m/s) (0.571 s) + ½ (0 m/s²) (0.571 s)²

x = 2.86 m

Rounded to two significant figures, the marble travels 2.9 meters in the x direction.

5 0
3 years ago
Which perspective best explains the bystander effect whereby individuals will be less likely to help someone in need because of
DerKrebs [107]
The perspective which best explain this is SOCIO-CULTURAL PERSPECTIVE.
Socio-cultural perspective is a theory which explains the awareness of situations surrounding people and how their behavior is determined by their environment, culture and social values.
3 0
3 years ago
6. If a bicyclist, with initial velocity of zero, steadily gained speed until reaching a final velocity of 39m/s, how far would
Bezzdna [24]

Answer:

  175 m

Explanation:

The average velocity for constant acceleration is the average of the beginning and ending velocities. That is (0+39)/2=19.5 m/s. If the bicyclist rides for 9 seconds, the distance traveled is ...

  (9 s)(19.5 m/s) = 175.5 m

She would travel 175.5 meters in that time.

7 0
3 years ago
Show which of the following functional forms work or do not work as solutions to this differential equation (known as 'the wave
Akimi4 [234]

Answer:

E = A cos (Bx + Ct) and E = A cos (Bx + Ct + D)

Explanation:

The wave equation is

           d²y / dx² = 1 /v²  d²y / dt²

Where v is the speed of the wave

Let's review the solutions

In this case y = E

a) E = A sin Bt

 This cannot be a solution because the part in x is missing

      dE / dx = 0

b) E = A cos (Bt + c)

There is no solution missing the Part in x

         dE / dx = 0

c) E = A x² t²

The parts are fine, but this solution is not an oscillating wave, so it is not an acceptable solution of the wave equation

d) E = A cos (Bx + Ct) and E = A cos (Bx + Ct + D)

Both are very similar

Let's make the derivatives

       dE / dx = -A B sin (Bx + Ct + D)

      d²E / dx² = -A B² cos (Bx + Ct + D)

      dE / dt = - A C sin (Bx + Ct + D)

      d²E / dt² = -A C² cos (Bx + Ct + D)

We substitute in the wave equation

      -A B² cos (Bx + Ct + D) = 1 / v² (-A C² cos (Bx + Ct + D))

       B² = 1 / v² (C²)

       v² = (C / B)²

       v = C / B

We see that the two equations can be a solution to the wave equation, the last one is the slightly more general solution

8 0
3 years ago
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