1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sunny_sXe [5.5K]
3 years ago
9

a marine biologist wants to know the total vertical distance a dolphin travel during a jump with the surface of the water being

zero is started underwater at -35 ft jump up and out of the water the 27 ft and return to the water to swim at -18 feet what is the total vertical distance the dolphin traveled?
Physics
2 answers:
Yuki888 [10]3 years ago
5 0

Answer:

107 feet is the total vertical distance the dolphin traveled.

Explanation:

Negative sign in front of the distance value is just to define the distance covered by dolphin underwater that is beneath the surface of the water

Before jump

Vertical distance covered by dolphin below the surface of water before coming out= 35 feet

Vertical distance covered by dolphin after coming out of the surface of water = 27 feet

After jump

Vertical distance covered by dolphin above the surface of water after jumping = 27 feet

Vertical distance covered by dolphin below the surface of water after jumping = 18 feet

The total vertical distance the dolphin traveled:

35 feet + 27 feet + 27 feet + 18 feet = 107 feet

marin [14]3 years ago
3 0

From the starting depth to the surface, the vertical distance is 35 ft.

From the surface to the peak of the jump, the vertical distance is 27 ft.

From the peak of the jump to the surface, the vertical distance is 27 ft.

From the surface to the ending depth, the vertical distance is 18 ft.

Then the total vertical distance is ...

  35 ft + 27 ft + 27 ft + 18 ft = 107 ft

You might be interested in
The muscular system and the skeletal system of the human body work together to
AlladinOne [14]
 A. Allow movement.  
Muscles connect to your skeleton and they contract and move the skeleton along. <span>They help the process of movement happen in a smoother manner.</span>
4 0
2 years ago
Read 2 more answers
From the Bohr Model diagram, assuming the atom is neutral, what element is represented by the diagram? A) Argon B) Chlorine Elim
viktelen [127]

The actual answer is B) Chlorine

According to the Bohr Model diagram, the atom has seventeen electrons. This makes it Chlorine.


Sorry if i'm late!!

5 0
3 years ago
Read 2 more answers
The Acorn Insurance Company charges $3.50 for each unit of coverage under a block of 1-year term life insurance policies. The an
ICE Princess25 [194]

Answer:

$175

Explanation:

Insurance premium is expressed as a rate $1000

($3.50 per $1000)

Therefore;

Annual premium= $50000x$3.50/$1000

= $175

8 0
3 years ago
Use the graph for both answers.
Natasha2012 [34]

1. A. 6.00 sec

The graph shows the velocity of an object (y-axis) versus the time (x-axis). In order to find when the magnitude of the velocity reaches 36.00 km/h, we should find the time t (x-coordinate) at which the velocity (y-coordinate) is 36.

By looking at the graph, we see that this occurs when t=6.00 s.


2. A. positive acceleration

In a velocity-time graph like this one, the slope of the curve corresponds to the acceleration of the object. In fact, acceleration is defined as:

a=\frac{\Delta v}{\Delta t}

where \Delta v is the variation of velocity and \Delta t is the variation of time. We see that this quantity corresponds to the slope of the curve in the graph (in fact, \Delta v represents the increment of the y coordinate, while \Delta t represents the increment of the x coordinate). So, a positive slope means a positive acceleration: in this case, the slope is positive, so the acceleration is also positive.


3 0
3 years ago
Read 2 more answers
A far-sighted person has a near-point of 80 cm. To correct their vision so that they can see objects that are as close as 10 cm
bekas [8.4K]

Answer:

f = 8.89 cm

Explanation:

As we know that Far sighted person has near point shifted to 80 cm distance

so he is able to see the object 80 cm

now the distance of lens from eye is 2 cm

and the person want to see the objects at distance 10 cm

so here the image distance from lens is 80 cm and the object distance from lens is 8 cm

now from lens formula we have

\frac{1}{d_i} + \frac{1}{d_0} = \frac{1}{f}

-\frac{1}{80} + \frac{1}{8} = \frac{1}{f}

f = 8.89 cm

3 0
3 years ago
Other questions:
  • Which of the following is an example of newton second law of motion?
    5·1 answer
  • If the distance between two positive point charges is tripled, then the strength of the electrostatic repulsion between them wil
    14·1 answer
  • If it takes 600 N to move a box 5 meters, how much work is done on the box?
    9·1 answer
  • What is 1000 N in kilograms
    10·1 answer
  • A diver shines an underwater searchlight at the surface of a pond (n = 1.33). At what angle (relative to the surface) will the l
    11·1 answer
  • Gravitational force between two objects depends on
    10·2 answers
  • Define the focus of a concave lens ​
    10·1 answer
  • The duration between the emission of the sound from the echo reception is: t - 1.5 s. the distance between the observer and the
    6·2 answers
  • 1. What is the kinetic energy of a 94 kg basketball player running at 7.3 m/s?
    14·1 answer
  • What is its time interval between the release of the ball and the time it reaches its maximum height? Its initial vertical speed
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!