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oee [108]
3 years ago
12

During an endothermic phase change, what happens to the potential energy and the kinetic energy?

Chemistry
2 answers:
tester [92]3 years ago
5 0

Answer:

d. Potential energy increases, and kinetic energy stays the same.

Explanation:

This is correct on edge.

The answers to the Enthalpy and Phase Changes quiz are:

1. D 25.0 kJ

2. A Delta Hfus

3. C heat of fusion

4. D Potential energy increases, and kinetic energy stays the same.

5. B This is an exothermic reaction that involves freezing.

6. B a thermometer

7. C 549 g

8. B Energy is absorbed, and potential energy increases.

9. D a solid to a liquid

10. C the periodic table

antiseptic1488 [7]3 years ago
4 0

During endothermic phase change, the potential energy of the system always increases while the kinetic energy of the system remains constant. The potential energy of the reaction increases because energy is been added to the system from the external environment.

<u>Explanation</u>:

  • Those are three distinct methods for demonstrating a specific energy condition of an object. They don't affect one another.
  • "Potential Energy" is a relative term showing a release of possible energy to the environment. If we accept its pattern as the overall energy state of a compound, at that point, an endothermic phase change would infer an increase in "potential" as energy is being added to the compound by the system.
  • A phase change will display an increase in the kinetic energy at whatever point the compound is transforming from a high density to a low dense phase. The kinetic energy will decrease at whatever point the compound is transforming from a less dense to high dense phase.
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A rigid container is filled with chlorine gas. The gas has a pressure of 2.75 bar. The tank is then cooled down to -20.0oC at wh
Gnom [1K]

Answer:

Original temperature (T1) = - 37.16°C

Explanation:

Given:

Gas pressure (P1) = 2.75 bar

Temperature (T2) = - 20°C

Gas pressure (P2) = 1.48 bar

Find:

Original temperature (T1)

Computation:

Using Gay-Lussac's Law

⇒ P1 / T1 = P2 / T2

⇒ 2.75 / T1 = 1.48 / (-20)

⇒ T1 = (2.75)(-20) / 1.48

⇒ T1 = -55 / 1.48

⇒ T1 = - 37.16°C

Original temperature (T1) = - 37.16°C

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Question 15 of 35
Solnce55 [7]

The statements that describe how the pond turned into the bog is as follows: Large water plants grew in shallow water around the edge of the pond.

<h3>What is a pond?</h3>

Pond is an inland body of standing water, either natural or man-made, that is smaller than a lake.

A bog is an area of decayed vegetation (particularly sphagnum moss) which forms a wet spongy ground too soft for walking.

This means that a pond can become a bog when existing plants in the pond decays until the land becomes soft.

Therefore, the statements that describe how the pond turned into the bog is as follows: Large water plants grew in shallow water around the edge of the pond.

Learn more about ponds and bogs at: brainly.com/question/9715563

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