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Mamont248 [21]
3 years ago
15

An experiment was preformed to test the effects of different types of fertilizers on the number of tomatoes produced by one type

of tomato plant. What is the experimental (independent) variable in this investigation?
A color of plant
B type of fertilizer
C number of tomatoes
D type of plant
Chemistry
1 answer:
alisha [4.7K]3 years ago
4 0
B Type of fertilizer

Hope it helps!
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2C2H2 + 5O2 → 4CO2 + 2 H2O How many grams of CO2 are required to react with exactly 3.00 mol of O2? 106 g 132 g 165 g 76.8 g
cricket20 [7]

Hey there!:

Given the reaction:

2 C2H2 + 5 O2 → 4 CO2 + 2 H2O

5 moles O2 ------------- 4 moles CO2

3.00 moles O2 ----------  ( moles of CO2 ?? )

moles of CO2 = 3.00 * 4 / 5

moles of CO2 =  12 / 5

moles of CO2 = 2.4 moles

So, molar  mass CO2 = 44.01 g/mol

Therefore:

1 mole CO2 -------------- 44.01 g

2.4 moles CO2 ---------- ( mass of CO2 )

mass of CO2 = 2.4 * 44.01 / 1

mass of CO2 = 106 g

Answer A


Hope that helps!

8 0
3 years ago
What is the evaluation of 60.1 x -9.2?
poizon [28]
That's the evaluation

5 0
3 years ago
Which is true about sugar dissolving in water?
gizmo_the_mogwai [7]
<span>The correct answer is "Sugar is the solute and water is the solvent". Why? Sugar can be dissolved by water itself, especially in hot water, which is why water is considered to be a solvent, while sugar is considered to be a solute because it can be dissolved.</span>
6 0
3 years ago
What is 140.2 in scientific notation
Akimi4 [234]

Answer:

1.402 * 10^2.

Explanation:

There are 3 digits before the decimal point so the exponent is 2.

4 0
3 years ago
Read 2 more answers
Many home barbeques are fueled with propane gas (C3H8)(C3H8). Part A What mass of carbon dioxide is produced upon the complete c
Andrew [12]

Answer:

41264 g of CO₂

Explanation:

Combustion reaction is:

C₃H₈ + 5O₂ →  3CO₂  +  4H₂O

1 mol of propane react to 5 moles of oxygen in order to proudce 3 moles of carbon dioxide and 4 moles of water.

In a combustion reaction, our reactant reacts to oxygen and the products are always CO₂ and water.

We have the volume of propane but we need moles of it, so we need to apply density.

Density = mass / volume so mass = density . volume.

Density of propane is: 493 g/L

Mass of propane is 493 g/L . 27.9L = 13754.7 g

We convert mass to moles: 13754.7 g . 1 mol/ 44g = 312.6 moles

According to reaction, 1 mol of propane can produce 3 moles of CO₂

Our 312.6 moles will produce 312.6 . 3 = 937.8 moles

We convert moles to mass: 937.8 mol . 44 g/mol = 41264 g

3 0
2 years ago
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