We are to find how long will it take to return to the ground?
Answer:
t = 0.48 sec
Step-by-step explanation:
We are given;
initial velocity; vi = 40 ft/s
hi = 70 ft
acceleration due to gravity; a = 32 ft/s²
Now, we are given that the rocket's height as a function of time is;
h = -12at² + vit + hi
At ground, h = 0
Plugging in the relevant values to obtain ;
0 = -12(32)t² + 40t + 70
-384t² + 40t + 70 = 0
The roots of the equation gives; t = 0.48 sec
3^3-2(5)^2-3(3)^3+-3(4)
27-50-81+-12
-116
Answer:
(0,0)
Step-by-step explanation:
(0, 3) + 4 = (0,7)
(0, 7) - 7 = (0,0)
Answer:c
Step-by-step explanation:
4 % = 4/100
Simplify the fraction.
4/100 = 1/25
<h3>
Answer: B. 2</h3>
How I got that answer:
The data set for Marcus is
2, 3, 5, 6, 6, 6, 7, 7, 7, 7, 7, 7, 8, 8, 8, 8, 8, 9, 10, 10
The five number summary is
- min = 2
- Q1 = 6
- median = 7
- Q3 = 8
- max = 10
So the interquartile range (IQR) is
IQR = Q3 - Q1
IQR = 8 - 6
IQR = 2
