since the car moves, the force needed to move is greater than the frictional forces opposing it
a = 3.17m/s²
<h2>The initial velocity is 2.3
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Explanation:
Suppose the speed of car at point A is u .
Its kinetic energy K = mu²
At point B , its kinetic energy = K
and its gravitational potential energy = K = m g h = 2 m g R
here height h = 2 R ( radius of circle )
From the principle of conservation of energy
m u² = m u² + 2 m g R
m u² = 2 m g R
Therefore u = = 2.3
The inner planets are closer to the sun, rockier and smaller. The outer planets are further from the sun, bigger and consisting primarily of gas.
Answer:
6.6 atm
Explanation:
Using the general gas law
P₁V₁/T₁ = P₂V₂/T₂
Let P₂ be the new pressure
So, P₂ = P₁V₁T₂/V₂T₁
Since V₂ = 2V₁ , P₁ = 12 atm and T₁ = 273 + t where t = temperature in Celsius
T₂ = 273 + 2t (since its Celsius temperature doubles).
Substituting these values into the equation for P₂, we have
P₂ = P₁V₁(273 + 2t)/2V₁(273 + t)
P₂ = 12(273 + 2t)/[2(273 + t)]
P₂ = 6(273 + 2t)/(273 + t)]
assume t = 30 °C on a comfortable spring day
P₂ = 6(273 + 2(30))/(273 + 30)]
P₂ = 6(273 + 60))/(273 + 30)]
P₂ = 6(333))/(303)]
P₂ = 6.6 atm
Answer:
Explanation:
The acceleration experimented while taking a curve is the centripetal acceleration . Since , we have that:
They take the same curve, so we have:
Which means:
And finally we obtain: