Answer:
The resistance of the first resistor is, R₁ = 10 Ω
Explanation:
Given data,
The potential of the cell v = 3 V
The current through the first resistor, I = 0.2 A
The P.D across the first resistor, v₁ = 2.0 V
Let R₁, and R₂ be the resistance of the resistors,
Since the voltage across the series connection is,
v = v₁ + v₂
Substituting the values
3 V = 2 V + v₂
∴ v₂ = 1 V
Hence, the P.D across the second resistor is, v₂ = 1 V
The resistance of the first resistor is,
R₁ = v₁ / I
= 2 V / 0.2 A
= 10 Ω
Hence, the resistance of the first resistor is, R₁ = 10 Ω
