A box with a weight of 50 N rests on a horizontal surface. A person pulls horizontally on it with a force of 15 N and it does no
t move. To start it moving, a second person pulls vertically upward on the box. If the coefficient of static friction is 0.4, what is the smallest vertical force for which the box moves
1 answer:
Answer:
12.5N
Explanation:
Data;
W = 50N
Fh = 15N
μ = 0.4
Fv= ?
The second attachment is showing the resolution of the vectors.
The normal force acting on the box (N) = W - Fv
The frictional force ( ⃗f) = Fh
Frictional force ⃗f = μN = μ(W - Fv)
μW - μFv = Fh
Fv = W - (Fh/μ)
Fv = 50 - (15/0.4) = 50 - 37.5
Fv = 12.5N
The smallest vertical force which moves the box is 12.5N
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Answer:
Explanation:
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Answer:
37 W
Explanation:
Power is the time rate of dissipation or absorbing energy. The power supplied or absorbed by an element is the product of the current flowing through the element and the voltage across the element. Power is measured in watts. If the power is positive then it is absorbed by the element and if it is negative then it is supplied by the element.
Power = voltage * current
For element A: Power = 36 V * -4 A = -144 W
For element B: Power = -20 V * -4 A = 80 W
For element C: Power = -24 V * 4 A = -94 W
For element D: Power = -80 V * -1.5 A = 120 W
For element E: Power = 30 V * 2.5 A = 75 W
The total power developed in the circuit = sum of power through the element = (-144 W) + 80 W + (-94 W) + 120 W + 75 W = 37 W
