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anygoal [31]
2 years ago
6

Find the value of X.

Mathematics
1 answer:
klemol [59]2 years ago
5 0

Answer:

I think answer is 3

Step-by-step explanation:

BD = DA

BE = EC

Now, BD/BE = DA/EC

or, x + 5/2x = 4/3

or, 3x + 15 = 8x

or, 15 = 8x - 3x

or, 15 = 5x

or, 15/5 = x

or, 3 = x

Therefore x = 3 <u>Ans</u>

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Just find the volume of a triangular prism.

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The answer is not 1465.5. Every month, Ms. Thomas pays her car loan through automatic payments (withdrawals) from her savings ac
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Answer:

$244.25

Step-by-step explanation:

First, the question is asking what the change in her savings account balance is each month. So, you know that you are looking for the amount that is lost each month. When it says that at the end of the year, she has payed $2,931 , what is implied is that she has spent that much over 12 months. So all that is needed to do is divide her balance change over the year by 12 to find the monthly balance change.

4 0
2 years ago
Please help properties of exponents
defon

Answer:

Step-by-step explanation:

3. c^{11} add exponents

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3 0
3 years ago
24. Find the area of the shaded region:
Monica [59]

Answer:

A = 5x³ + 17x² - 35x - 30

Step-by-step explanation:

the shaded area (A) is calculated as

A = outer area - inner area

   = (5x + 3)(x² + 4x - 10) - 3x(2x - 1) ← distribute parenthesis

   = 5x³ + 20x² - 50x + 3x² + 12x - 30 - (6x² - 3x)

  = 5x³ + 23x² - 38x - 30 - 6x² + 3x ← collect like terms

  = 5x³ + 17x² - 35x - 30

7 0
2 years ago
Read 2 more answers
NASA is conducting an experiment to find out the fraction of people who black out at G forces greater than 6. In an earlier stud
SSSSS [86.1K]

Answer:

The large sample n = 190.44≅190

The  large  sample would be required in order to estimate the fraction of people who black out at 6 or more Gs at the 85% confidence level with an error of at most 0.04 is n = 190.44

<u>Step-by-step explanation</u>:

Given  population proportion was estimated to be 0.3

p = 0.3

Given maximum of error E = 0.04

we know that maximum error

M.E = \frac{Z_{\alpha } \sqrt{p(1-p)} }{\sqrt{n} }

The 85% confidence level z_{\alpha } = 1.44

\sqrt{n} = \frac{Z_{\alpha } \sqrt{p(1-p)} }{m.E}

\sqrt{n} = \frac{1.44X\sqrt{0.3(1-0.3} }{0.04}

now calculation , we get

√n=13.80

now squaring on both sides n = 190.44

large sample n = 190.44≅190

<u>Conclusion</u>:-

Hence The  large  sample would be required in order to estimate the fraction of people who black out at 6 or more Gs at the 85% confidence level with an error of at most 0.04 is n = 190.44

7 0
3 years ago
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