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jarptica [38.1K]
3 years ago
7

A survey found that 39% of the population owned dogs, 22% owned

Mathematics
2 answers:
Dmitriy789 [7]3 years ago
6 0

Answer:

53% probability that a person owns a cat or a dog.

Step-by-step explanation:

I am going to solve this question building the Venn's diagram of these probabilities,

We have that:

P(A) is the probability that a person owns a dog.

P(B) is the probability that a person owns a cat.

8% of the population owned both a cat and a dog

This means that P(A \cap B) = 0.08

22% owned cats

This means that P(B) = 0.22

39% of the population owned dogs

This means that P(A) = 0.39

Find the probability that a person owns a cat or a dog.

This is P(A \cup B), which is given by:

P(A \cup B) = P(A) + P(B) - P(A \cap B)

So

P(A \cup B) = 0.39 + 0.22 - 0.08 = 0.53

53% probability that a person owns a cat or a dog.

Sergio039 [100]3 years ago
4 0

Answer:

0.53

Step-by-step explanation:

Percentage who owned dogs, n(D)=39%

Percentage who owned cats, n(C)=22%

Percentage who owned both dogs and cats, n(C\cap D)=8\%

From Probability Theory

P(C\cup D)=P(C)+P(D)-P(C\cap D)\\=0.22+0.39-0.08\\P(C\cup D)=0.53

The probability that a person owns a cat or a dog therefore is 0.53.

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Question 7: $3945

78,900÷100×5= 3,945

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Question 8: I think it may be $675.46 ( but I'm not sure)

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$1010÷12= $84.20

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Find the equation of the line passing through the following : (-1;6) and (-3;0)
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Answer:

Step-by-step explanation:

(x_{1} , y_{1}) = (-1,6)\\\\(x_{2},y_{2}) = ( -3, 0)\\\\Slope =\dfrac{y_{2}-y_{1}}{x_{2}-x_1}}\\\\\\=\dfrac{0-6}{-3+1}\\\\\\=\dfrac{-6}{-2}\\\\=3

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