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3 years ago

A survey found that 39% of the population owned dogs, 22% owned

Mathematics

2 answers:

Dmitriy789 [7]3 years ago

6 0

Answer:

53% probability that a person owns a cat or a dog.

Step-by-step explanation:

I am going to solve this question building the Venn's diagram of these probabilities,

We have that:

P(A) is the probability that a person owns a dog.

P(B) is the probability that a person owns a cat.

8% of the population owned both a cat and a dog

This means that $P(A \cap B) = 0.08$

22% owned cats

This means that $P(B) = 0.22$

39% of the population owned dogs

This means that $P(A) = 0.39$

Find the probability that a person owns a cat or a dog.

This is $P(A \cup B)$ , which is given by:

$P(A \cup B) = P(A) + P(B) - P(A \cap B)$

$P(A \cup B) = 0.39 + 0.22 - 0.08 = 0.53$

53% probability that a person owns a cat or a dog.

Sergio039 [100]3 years ago

4 0

Answer:

0.53

Step-by-step explanation:

Percentage who owned dogs, n(D)=39%

Percentage who owned cats, n(C)=22%

Percentage who owned both dogs and cats, $n(C\cap D)=8\%$

From Probability Theory

$P(C\cup D)=P(C)+P(D)-P(C\cap D)\\=0.22+0.39-0.08\\P(C\cup D)=0.53$

The probability that a person owns a cat or a dog therefore is 0.53.

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In this case it is 0, not 2, which was my first and wrong answer

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3 years ago

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PSYCHO15rus [73]

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3 years ago

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AURORKA [14]

Answer:

Minimum is a 4th Degree

Positive; Even

$x=-4, -1\text{ Odd Multiplicity}\\x=3\text{ Even Multiplicity}$

Step-by-step explanation:

Part 1)

The minimum degree of our function will be 4.

Looking at the graph, we know that the graph crosses the x-axis at -4 and -1. Since it crosses through the x-axis at these two points, these two factors must have an odd multiplicity.

So, it can be anything 1, 3, 5, 7, etc.

However, we will choose the lowest one, 1.

Next, we know that the graph bounces off at 3.

So, it must have an even multiplicity. In other words, 2, 4, 6, 8, etc.

We choose the lowest one, 2.

Therefore, the minimum degree of our function will be 1+1+2 or 4.

Part 2)

The degree of our polynomial is (and will always be) even. Therefore, both ends of the graph will go in the same direction.

Recall the simplest even polynomial, the parent quadratic function. When the leading coefficient is positive, both of the ends go straight up.

This applies to all polynomials with even degrees.

Therefore, since the arms of the graph is going straight up towards positive infinity, the leading coefficient of our graph must be positive.

Part 3)

This is similar to Part 1.

We can see that the graph touches the x-axis at -4, -3, and 1. So, the zeros of the function is: $x=-4, -1, 3$

We know that it passes through $x=-4 \text{ and } x=-1$ . So, these two factors must have an odd multiplicity.

However, since the graph bounces off $x=3$ , this factor must have an even multiplicity.

And we're done!

7 0

3 years ago

Solve the inequality 15t > 180

bagirrra123 [75]

Answer:

t>12

Step-by-step explanation:

t>180/15

then divide 180 by 15

and you gey t>12

4 0

3 years ago

4/5 minus 1/3 plz i need help

IRISSAK [1]

Answer:

7/15

Step-by-step explanation:

Step 1

We can't subtract two fractions with different denominators. So you need to get a common denominator. To do this, you'll multiply the denominators times each other... but the numerators have to change, too. They get multiplied by the other term's denominator.

So we multiply 4 by 3, and get 12.

Then we multiply 1 by 5, and get 5.

Next we give both terms new denominators -- 5 × 3 = 15.

So now our fractions look like this:

−

Step 2

Since our denominators match, we can subtract the numerators.

12 − 5 = 7

So the answer is:

Step 3

Last of all, we need to simplify the fraction, if possible. Can it be reduced to a simpler fraction?

To find out, we try dividing it by 2...

Nope! So now we try the next greatest prime number, 3...

Nope! So now we try the next greatest prime number, 5...

Nope! So now we try the next greatest prime number, 7...

Nope! So now we try the next greatest prime number, 11...

No good. 11 is larger than 7. So we're done reducing.

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2 years ago