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3 years ago

When hydrogen is attached to the more highly electronegative oxygen atom in a water molecule?

1 answer:

6 0

Here is the full question with choices: When hydrogen is attached to the more highly electronegative oxygen atom in a water molecule, __________.?

A. the hydrogen atom becomes partially positive

B. the electronegative atom becomes strongly positive

C. the hydrogen atom becomes partially negative

D. the oxygen atom becomes partially negative

The answers are A and D. The oxygen holds onto the electrons more of the time so is slightly negative, making H slightly positive and thus making a polar covalent bond.

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Which compounds are lewis acids? select all that apply. (ch3ch2)2hc+ cl3c− ch3nh2 bbr3?

alexandr402 [8]

The Lewis acids are electron pair acceptors due to the availability of vacant orbitals they accept electrons from the donor compounds.

$(CH_3CH_2)_2CH^{+}$ is a Lewis acid due to the unfilled valence shell on carbon atom (possessing positive charge) it accepts electron readily.
$CCl_{3}^{-}$ is not a Lewis acid due to the presence of negative charge which represents that there are electrons available for donation.
$CH_3NH_2$ is not a Lewis acid due to the presence of lone pair on nitrogen which is easily donated to the acceptors.
$BBr_3$ is a Lewis acid due to the availability of vacant p-orbital on boron atom.

Hence, $(CH_3CH_2)_2CH^{+}$ and $BBr_3$ are Lewis acids.

3 0

2 years ago

Question 25———-A, YA are two isotopes of element A.

lakkis [162]

Answer:

Option C. 1

Explanation:

Step 1:

Determination of the Neutron of both isotopes. This is illustrated below.

For isotope y xA:

Mass number = y

Atomic number = x

Neutron =..?

Atomic number = proton number = x

Mass number = Proton + Neutron

y = x + Neutron

Rearrange

Neutron = y – x

For isotope (y + 1) xA:

Mass number = y + 1

Atomic number = x

Neutron =.?

Atomic number = proton number = x

Mass number = Proton + Neutron

y + 1 = x + Neutron

Rearrange

Neutron = y + 1 – x

Step 2:

Determination of the difference between the neutron number of both isotopes. This is illustrated below:

For isotope y xA:

Neutron number = y – x

For isotope (y + 1) xA:

Neutron number = y + 1 – x

Difference in neutron number

=> (y + 1 – x) – (y – x)

=> y + 1 – x – y + x

Rearrange

=> y – y + 1 – x + x

=> 1

Therefore, the difference in the neutron number of both isotopes is 1

6 0

3 years ago

Using the equations 2 Sr(s) + O₂ (g) → 2 SrO (s) ∆H° = -1184 kJ/mol SrO (s) + CO₂ (g) → SrCO₃ (s) ∆H° = -234 kJ/mol CO₂ (g) → C(

kkurt [141]

Answer: The $\Delta H^o_{rxn}$ for the reaction is 72 kJ.

Explanation:

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

$2SrCO_3(s)\rightarrow 2Sr(s)+2C(s)+3O_2(g)$ $\Delta H^o_{rxn}=?$

The intermediate balanced chemical reaction are:

(1) $2Sr(s)+O_2(g)\rightarrow 2SrO(s)$ $\Delta H_1=-1184kJ$

(2) $SrO(s)+CO_2(g)\rightarrow SrCO_3(s)$ $\Delta H_2=-234kJ$ ( × 2)

(3) $CO_2(g)\rightarrow C(s)+O_2(g)$ $\Delta H_3=394kJ$ ( × 2)

The expression for enthalpy of the reaction follows:

$\Delta H^o_{rxn}=[1\times (\Delta H_1)]+[2\times (-\Delta H_2)]+[2\times (\Delta H_3)]$

Putting values in above equation, we get:

$\Delta H^o_{rxn}=[(1\times (-1184))+(2\times -(-234))+(2\times (394))]=72kJ$

Hence, the $\Delta H^o_{rxn}$ for the reaction is 72 kJ.

4 0

3 years ago

What is the total gas pressure in a sealed flask that contains oxygen at a partial pressure of 0.35 atm and water vapor at a par

Fofino [41]

According to Dalton's Law, in a mixture of non-reacting gasses, thetotal pressure exerted is the sum of the partial pressures of the component gasses. In more complicated circumstances, equilibrium states come into effect, but fortunately for us, oxygen is non-reactive with water vapor.

5 0

3 years ago

Calculate the percent dissociation of trimethylacetic acid in a aqueous solution of the stuff. You may find some useful data in

LuckyWell [14K]

Answer:

percentage dissociation of trimethylacetic acid in a 0.57M aqueous solution = 0.40%

Explanation:

check attachment below for more information o the answer.

3 0

3 years ago