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Paha777 [63]
3 years ago
5

The mass of amu of 710 iron atoms

Chemistry
1 answer:
shusha [124]3 years ago
5 0
The atomic mass unit of 710 Fe atoms would be equal to 41125 amu. We calculate this by first dividing with the avogadro's number which is 6.022x10^23. We obtain the number of moles, then we multiply with the molar mass to obtain grams. Lastly, divide with 1.6x10^-24 to obtain amu.

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Answer:

25% thorium will left after 50 days.

Explanation:

Half life:

A nuclear half is the time period of radioactive material in which its amount remain halved.

In given question it is stated that the half life thorium-234 is 25 days. Which means after passing the 25 days the amount of thorium must be halved of original amount.

For example,

If the original concentration was 100%, than after 25 days it will be 50%.

After 50 days amount of thorium left:

Number of half life = T (elapsed) / T half life

Number of half life = 50/25

Number of half life =  2

At first half life amount of thorium left = 100/2 = 50

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Total amount decayed = 50+25 = 75

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