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3 years ago

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The mass of amu of 710 iron atoms

1 answer:

shusha [124]3 years ago

5 0

The atomic mass unit of 710 Fe atoms would be equal to 41125 amu. We calculate this by first dividing with the avogadro's number which is 6.022x10^23. We obtain the number of moles, then we multiply with the molar mass to obtain grams. Lastly, divide with 1.6x10^-24 to obtain amu.

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3 years ago

The density of a rock that was a mass of 454 grams and a volume of 100 cm3

puteri [66]

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The answer is

<h2>4.54 g/cm³</h2>

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$density = \frac{mass}{volume} \\$

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<h3>4.54 g/cm³</h3>

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3 0

3 years ago

What is the final temperature of the solution formed when 1.52 g of NaOH is added to 35.5 g of water at 20.1 °C in a calorimeter

Inessa [10]

Answer : The final temperature of the solution in the calorimeter is, $31.0^oC$

Explanation :

First we have to calculate the heat produced.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy change = -44.5 kJ/mol

q = heat released = ?

m = mass of $NaOH$ = 1.52 g

Molar mass of $NaOH$ = 40 g/mol

$\text{Moles of }NaOH=\frac{\text{Mass of }NaOH}{\text{Molar mass of }NaOH}=\frac{1.52g}{40g/mole}=0.038mole$

Now put all the given values in the above formula, we get:

$44.5kJ/mol=\frac{q}{0.038mol}$

$q=1.691kJ$

Now we have to calculate the final temperature of solution in the calorimeter.

$q=m\times c\times (T_2-T_1)$

where,

q = heat produced = 1.691 kJ = 1691 J

m = mass of solution = 1.52 + 35.5 = 37.02 g

c = specific heat capacity of water = $4.18J/g^oC$

$T_1$ = initial temperature = $20.1^oC$

$T_2$ = final temperature = ?

Now put all the given values in the above formula, we get:

$1691J=37.02g\times 4.18J/g^oC\times (T_2-20.1)$

$T_2=31.0^oC$

Thus, the final temperature of the solution in the calorimeter is, $31.0^oC$

4 0

3 years ago