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koban [17]
3 years ago
15

______________ forces are between different ATOMS of the SAME molecule. ______________ forces are between different MOLECULES of

a substance.
A. Intermolecular; Intramolecular
B. Intramolecular; Intrermolecular
C. Intermolecular; Polar
D. Polar; Intramolecular
Chemistry
2 answers:
777dan777 [17]3 years ago
5 0

Hey there!

Your answer is B. Intramolecular; intermolecular.

Intramolecular forces are the forces that keep the atoms together in the molecule.

Intermolecular forces are the forces that are different molecules interacting with each other.

You can remember this by thinking about the prefixes inter- and intra-. Inter- refers to open systems within groups. The groups are the different molecules which are interacting with each other.

Intra-, however, refers to the closed system inside of a single group. The single group is the one molecule, and the interactions are happening between the atoms within the molecule.

Hope this helps!

hichkok12 [17]3 years ago
4 0
It would be B that the answer!
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Answer:

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Explanation:

Using the derived expression from Arrhenius Equation

In \ (\frac{k_2}{k_1}) = \frac{E_a}{R}(\frac{T_2-T_1}{T_2*T_1})

Given that:

time t_1 = 8.3 days = (8.3 × 24 ) hours = 199.2 hours

time t_2 = 10.6 hours

Temperature T_1 = 0° C = (0+273 )K = 273 K

Temperature T_2 = 30° C = (30+ 273) = 303 K

Rate = 8.314 J / mol

Since (\frac{k_2}{k_1}=\frac{t_2}{t_1})

Then we can rewrite the above expression as:

In \ (\frac{t_2}{t_1}) = \frac{E_a}{R}(\frac{T_2-T_1}{T_2*T_1})

In \ (\frac{199.2}{10.6}) = \frac{E_a}{8.314}(\frac{303-273}{273*303})

2.934 = \frac{E_a}{8.314}(\frac{30}{82719})

2.934 = \frac{30E_a}{687725.766}

30E_a = 2.934 *687725.766

E_a = \frac{2.934 *687725.766}{30}

E_a =67255.58 \ J/mol

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