n - number of mole
M(CO2) = 12.0 +16.0*2 = 44.0 mg/mmol
M(H2O) = 2*1.0 +16.0= 18.0 mg/mmol
1) 14.242 mg of CO2*1 mmol/44.0g =0.32368 mmol CO2
0.32368 mmol CO2 has 0.32368 mmol C
2) 0.32368 mmol C*12 mg/1 mmol= 3.88418 mg C
3) 4.083 mg of H2O * 1 mmol/18 mg = 0.226833 mmol H2O
0.226833 mmol H2O has 2*0.226833 mmol H = 0.453666 mmol H
4) 0.453666 mmol H*1 mg/1mmol = 0.453666 mg H
5) Mass of N = 5.250 mg - 3.88418 mg (C) - 0.453666 mg (H)≈ 0.912 mg N
0.912 mg N * 1 mmol/14.0 mg = 0.0652 mmol N
6) n(C) : n(H) : n(N) = 0.32368 mmol C : 0.453666 mmol H : 0.0652 mmol N
0.0652 mmol N is a smallest value.
n(C) : n(H) : n(N) = (0.32368 mmol/0.0652 mmol) C : (0.453666 mmol H/0.0652 mmol) : (0.0652mmol/0.0652 mmol)N = 5 : 7 : 1
n(C) : n(H) : n(N) = 5 : 7 : 1
Empirical formula : C5H7N.
