Answer:
-4n - 11
Step-by-step explanation:
Step 1: Convert words into an expression
11 less than the product of a number and -4
(n * -4) - 11
<em>-4n - 11</em>
<em />
Answer: -4n - 11
<u>If needed solve</u>
-4n - 11 + 11 = 0 + 11
-4n / -4 = 11 / -4
<em>n = -2.75</em>
Answer: The answer is 6n+7y
Step-by-step explanation: All you have to do is add like terms
No. when the line reaches 4 on the x axis it is at 13 on the y axis.
Firstly look at the options carefully and we will get to know that two answer options are incorrect because 2 of them are representing AT MOST SIGN which we don't need. So in that way Options B and D are eliminated.
So Now we are left with 2 options A and C. Lets figure it out.
We know that Carlos has 5 complete set with 4 individual figures and josh has 3 complete sets with 14 individual figures.
So lets write in the numerical language:-
let us assume that complete sets are X.
ATQ,
5x + 4 ≥ 3x + 14
subtracting 3x from both sides.
5x -3x + 4 ≥ 14
2x + 4 ≥ 14
subtracting 4 from both sides
2x ≥ 14 - 4
2x ≥ 10
dividing both sides by 2
x ≥ 5 Answer
So correct answer option is C
Check the picture below.
well, we want only the equation of the diametrical line, now, the diameter can touch the chord at any several angles, as well at a right-angle.
bearing in mind that <u>perpendicular lines have negative reciprocal</u> slopes, hmm let's find firstly the slope of AB, and the negative reciprocal of that will be the slope of the diameter, that is passing through the midpoint of AB.
![\bf A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{1}}}\implies \cfrac{-3}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{slope of AB}}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{\textit{\underline{negative reciprocal} and slope of the diameter}}{\cfrac{4}{3}}](https://tex.z-dn.net/?f=%5Cbf%20A%28%5Cstackrel%7Bx_1%7D%7B1%7D~%2C~%5Cstackrel%7By_1%7D%7B4%7D%29%5Cqquad%20B%28%5Cstackrel%7Bx_2%7D%7B5%7D~%2C~%5Cstackrel%7By_2%7D%7B1%7D%29%20~%5Chfill%20%5Cstackrel%7Bslope%7D%7Bm%7D%5Cimplies%20%5Ccfrac%7B%5Cstackrel%7Brise%7D%20%7B%5Cstackrel%7By_2%7D%7B1%7D-%5Cstackrel%7By1%7D%7B4%7D%7D%7D%7B%5Cunderset%7Brun%7D%20%7B%5Cunderset%7Bx_2%7D%7B5%7D-%5Cunderset%7Bx_1%7D%7B1%7D%7D%7D%5Cimplies%20%5Ccfrac%7B-3%7D%7B4%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bslope%20of%20AB%7D%7D%7B-%5Ccfrac%7B3%7D%7B4%7D%7D%5Cqquad%20%5Cqquad%20%5Cqquad%20%5Cstackrel%7B%5Ctextit%7B%5Cunderline%7Bnegative%20reciprocal%7D%20and%20slope%20of%20the%20diameter%7D%7D%7B%5Ccfrac%7B4%7D%7B3%7D%7D)
so, it passes through the midpoint of AB,
so, we're really looking for the equation of a line whose slope is 4/3 and runs through (3 , 5/2)
