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attashe74 [19]
3 years ago
9

EASY POINTS!!!! WORTH 30 POINTS

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
3 0

Would a bake sale flyer work?

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Nimisha wants to draw a wheel like the one shown. Each shaded part of the wheel should be one-third of each unshaded part. What
ivolga24 [154]

Answer:

Each shade has a 22.5 degree angle from the middle

Each unshaded has a 67.5 degree angle from the middle.

Step-by-step explanation:

You can solve this by making each unshaded part equal to x and each shaded part equal 1/3x it is a circle so it has to equal 360 so you end up with:

x + 1/3x + x + 1/3x + x + 1/3x + x + 1/3x = 360

Combine Like terms:

16/3x = 360

Multiply both sides by the opposite:

(3/16) (16/3x) = (360) (3/16)

x=135/2 or x=67.5

Then you can plug 67.5 in for x:

1/3x ---> 1/3(67.5) = 22.5

3 0
4 years ago
This is kinda confusing can someone help explain!!
AURORKA [14]

Answer: all i can say is this for an edu guess

2 6 and 4 would be 40 or 30

3 5 and 7 would be 110 or 120

8 would be 20 or 10

also this was the first answer

7 0
3 years ago
Read 2 more answers
What is the product of and (6+5i) and (3-7i) ?<br><br> -17-27i<br> -17+27i<br> 53+27i<br> 53-27i
USPshnik [31]
We are going to make the product step by step.
 We have:
 (6 + 5i) * (3-7i)
 Multiplying:
 ((6) * (3)) + ((6) * (- 7i)) + ((5i) * (3)) + ((5i) * (- 7i))
 Rewriting:
 18 - 42i + 15i - 35i ^ 2
 18 - 42i + 15i - 35 * (- 1)
 18 - 42i + 15i + 35
 53 - 27i
 Answer:
 
the product of and (6 + 5i) and (3-7i) is:
 
53-27i
5 0
4 years ago
In the diagram, ∠ADE ≅ ∠ABC.<br><br> The ratios___ and ___ are equal.
DiKsa [7]

Answer:

\frac{AD}{AB} = \frac{AE}{AC} = \frac{DE}{BC}

Step-by-step explanation:

triangle ADE and triangle ABC are similar

therefore, the ratio of their corresponding sides are equal

4 0
3 years ago
I need help please.
makkiz [27]

Answer:

see explanation

Step-by-step explanation:

Using the rules of radicals/ exponents

a^{m} × a^{n} = a^{(m+n)}

a^{\frac{m}{n} } ⇔ \sqrt[n]{a^{m} }

Simplifying each term

7\sqrt{x^{3} } = 7x^{\frac{3}{2} }

x\sqrt{9x}

= x × \sqrt{9} × \sqrt{x}

= x × 3 × x^{\frac{1}{2} }

= 3 × x^{(1+\frac{1}{2}) }

= 3x^{\frac{3}{2} }

Subtracting the 2 simplified like terms, that is

7x^{\frac{3}{2} } - 3x^{\frac{3}{2} }

= 4x^{\frac{3}{2} } ← return to radical form

= 4\sqrt{x^{3} }

8 0
3 years ago
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