Answer:
One solution.
Step-by-step explanation:
This is the only way I know how to solve it. These two expressions are equivalent to each other.
Answer:
5/20
Step-by-step explanation:
i used multiplycation
Answer:
false I did an example with 20 and the answer weren't the same
Answer:
Option D. ![272](https://tex.z-dn.net/?f=272)
Step-by-step explanation:
we know that
To evaluate the sum , use the formula
![S=\frac{1}{2}(a1+an)n](https://tex.z-dn.net/?f=S%3D%5Cfrac%7B1%7D%7B2%7D%28a1%2Ban%29n)
where
a1 is the first term
an is the last term
n is the number of terms
In this problem
For n=1 ------> a1=2(1)=2
For n=16 ------> an=2(16)=32
n=16 terms
substitute in the formula
![S=\frac{1}{2}(2+32)16](https://tex.z-dn.net/?f=S%3D%5Cfrac%7B1%7D%7B2%7D%282%2B32%2916)
![S=272](https://tex.z-dn.net/?f=S%3D272)
Answer:
x1 = 8+√10, x2 = 8 -√10
Step-by-step explanation:
x² - 16x + 54 = 0
![x = \frac{-b +/-\sqrt{b^{2} -4ac} }{2a} \\x = \frac{-(-16)+/-\sqrt{(-16)^{2} -4*1*54} }{2*1} \\\\\\x = \frac{16+/-\sqrt{(40)} }{2*1} = 8+/-\sqrt{10} \\\\x_{1} = 8+\sqrt{10}\\\\x_{2} =8-\sqrt{10}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B-b%20%2B%2F-%5Csqrt%7Bb%5E%7B2%7D%20-4ac%7D%20%7D%7B2a%7D%20%5C%5Cx%20%3D%20%5Cfrac%7B-%28-16%29%2B%2F-%5Csqrt%7B%28-16%29%5E%7B2%7D%20-4%2A1%2A54%7D%20%7D%7B2%2A1%7D%20%5C%5C%5C%5C%5C%5Cx%20%3D%20%5Cfrac%7B16%2B%2F-%5Csqrt%7B%2840%29%7D%20%7D%7B2%2A1%7D%20%3D%208%2B%2F-%5Csqrt%7B10%7D%20%5C%5C%5C%5Cx_%7B1%7D%20%3D%208%2B%5Csqrt%7B10%7D%5C%5C%5C%5Cx_%7B2%7D%20%3D8-%5Csqrt%7B10%7D)