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2 years ago

Find the arc length of the partial circle.

Mathematics

1 answer:

Kay [80]2 years ago

3 0

Answer:

12.42 units

Step by step explanation:

Given,

length of the radius = 2 units

Therefore, arc length of the complete circle = 2 × 3.14 × 2 units = 12.56 units

Therefore, arc length of the partial circle = 3/4 × 12.56 units

= 12.42 units

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Which value of X makes the quotient of (5x^5+90x^2-135x)/(x+3) undefined

faust18 [17]

Answer:

b) - 3

Step-by-step explanation:

If x = -3 , then

x + 3 = -3 + 3 = 0

So, denominator would become 0. So , anything divided by 0 is undefined

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2 years ago

If an equation ends with the answer 39=15 how many solutions are there?

Darina [25.2K]

Answer:

none

Step-by-step explanation:

there would be no solutions because 39 does not equal 15

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2 years ago

Suppose r(140°, P)(A) = B and (RPD←→∘RPC←→)(A) = B, what is m∠CPD?

NISA [10]

An angle bisector divides an angle into two equal halves.

The measure of angle $\angle CPD$ is 70 degrees

The complete question is an illustrates the concept of angle bisector;

Where:

$\angle RPD = 140^o$ , and line PC bisects $\angle RPD$

Because line PC bisects $\angle RPD$ , then it means that the measure of RPD is twice the measure of CPD:

So, we have:

$\angle RDP = 2 \times \angle CPD$

Substitute $\angle RPD = 140^o$

$140^o = 2 \times \angle CPD$

Divide both sides by 2

$70^o = \angle CPD$

Apply symmetric property of equality:

$\angle CPD = 70^o$

Hence, the measure of angle $\angle CPD$ is 70 degrees

Read more about angle bisectors at:

brainly.com/question/12896755

5 0

2 years ago

A binomial consists of———— terms

Softa [21]

Consists of two terms (A+B)

7 0

2 years ago

Read 2 more answers

A chemical balance needs to weigh 237g using weights of 50g, 20g, 10g and 1g. How many of each weight is needed?

Delicious77 [7]

The required number of weights used in chemical balance to weigh 237g is 4,1,1,7 respectively.

What is mathematical expression?

A mathematical expression expression in mathematical is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Here, it is given that :

A chemical balance needs to weigh 237g using weights of 50g, 20g, 10g and 1g.

Now, let us find the number of weights for each weight type :

For 50g weight the maximum number of weights needed will be 4 that is :

50g x 4 = 200g

Now, for 20g weight the maximum number of weights needed will be 1 that is :

20g x 1 = 20g

Now, for 10g weight the maximum number of weights needed will be 1 that is :

10g x 1 = 10g

Now, for 1g weight the maximum number of weights needed will be 7 that is :

1g x 7 = 7g

Adding all the weights we get :

200g + 20g + 10g + 7g = 237g;

which is the required weight and the number of weights used is 4,1,1,7 respectively.