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goldenfox [79]
3 years ago
13

At the beginning of the week, Naveen has 87 trading cards. On Monday, he gets 9 more. On Tuesday, he gives 16 away. On Wednesday

, he is given 3 by a friend. On Thursday, he sells all of his cards to a collector. The collector pays him a rate of c for every card that Naveen has. If Naveen earns $124.50 from the sale, what is c, the rate that the collector pays for each card?
Mathematics
2 answers:
Zanzabum3 years ago
5 0

$1.50 I just took the quiz

Zielflug [23.3K]3 years ago
4 0
He has 87 cards then he gets 9 more which is 96, he then gives 16 away which is 80, then he is given 3 which is 83 he sells all 83 cards to the collector & the collector gives him $124.50 each card is worth $1.50
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Mashcka [7]

Answer:

  • No, incorrect

Step-by-step explanation:

<u>Given</u>

  • Q(s) = -4s^3 + 7s^2 - 24;
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<u>Verifying zeroes</u>

Q(-4) =

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  • 344
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Q(1) =

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8 0
3 years ago
I think its identity but I'm not sure
victus00 [196]

Answer: C, you are correct

Step-by-step explanation:

7 0
3 years ago
Solve the Differential equation (x^2 + y^2) dx + (x^2 - xy) dy = 0
natita [175]

Answer:

\frac{y}{x}-2ln(\frac{y}{x}+1)=lnx+C

Step-by-step explanation:

Given differential equation,

(x^2 + y^2) dx + (x^2 - xy) dy = 0

\implies \frac{dy}{dx}=-\frac{x^2 + y^2}{x^2 - xy}----(1)

Let y = vx

Differentiating with respect to x,

\frac{dy}{dx}=v+x\frac{dv}{dx}

From equation (1),

v+x\frac{dv}{dx}=-\frac{x^2 + (vx)^2}{x^2 - x(vx)}

v+x\frac{dv}{dx}=-\frac{x^2 + v^2x^2}{x^2 - vx^2}

v+x\frac{dv}{dx}=-\frac{1 + v^2}{1 - v}

v+x\frac{dv}{dx}=\frac{1 + v^2}{v-1}

x\frac{dv}{dx}=\frac{1 + v^2}{v-1}-v

x\frac{dv}{dx}=\frac{1 + v^2-v^2+v}{v-1}

x\frac{dv}{dx}=\frac{v+1}{v-1}

\frac{v-1}{v+1}dv=\frac{1}{x}dx

Integrating both sides,

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\int{1-\frac{2}{v+1}}dv=lnx + C

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Now, y = vx ⇒ v = y/x

\implies \frac{y}{x}-2ln(\frac{y}{x}+1)=lnx+C

5 0
3 years ago
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Step-by-step explanation:

3 0
3 years ago
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Step-by-step explanation:

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