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Anton [14]
3 years ago
11

A company is presenting the sales data using a bar graph. The company asserts that the sales increased substantially from 2006 t

o 2008 using Bar Graph 1. Their competitor used the same sales data to produce Bar Graph 2. Which bar graph is misleading? How do you know?
Mathematics
2 answers:
ludmilkaskok [199]3 years ago
4 0

Answer: b.

Bar Graph 1 is misleading because the vertical axis does not start and 0 and the scale for the graph is 0.25 instead of 1.  

Genrish500 [490]3 years ago
3 0

Answer: b.

Bar Graph 1 is misleading because the vertical axis does not start and 0 and the scale for the graph is 0.25 instead of 1.  

Step-by-step explanation:

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Find the percent of increase from 40 gallons to 89 gallons. Round to the nearest tenth of a percent if necessary.
fredd [130]

Solution

- 89 gallons contains 40 gallons twice such that:

89=40+40+9

- This means that we can find at least 200% of 40 gallons in 89 gallons. This gives us what to expect.

- To get the percentage we are looking for, we should use the formula:

\frac{\text{new}}{\text{old}}\times100\text{ \%}

New, in this case, is 89 gallons, Old is 40 gallons.

- Thus, we can calculate the percentage as follows:

\begin{gathered} \frac{89}{40}\times100 \\ =2.225\times100 \\ =222.5\text{ \%} \end{gathered}

Thus, the answer is 222.5%

8 0
1 year ago
Compare the rates of change of the following items.
liq [111]

Answer:y=24(2-3)

Step-by-step explanation:

8 0
3 years ago
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Please help me with this!!!
Alex Ar [27]
He’s right !! He helps me with my problems!
4 0
3 years ago
Quadrilateral DEFG has vertices D(−2,4) , E(4,7) , F(10,3) , and G(8,0) .
fredd [130]

A rotation 270° counterclockwise about the origin is the same as rotation 90° clockwise about the origin and has a rule:

(x,y)→(y,-x).

Then:

  • D(−2,4)→D'(4,2)
  • E(4,7)→E'(7,-4)
  • F(10,3)→F'(3,-10)
  • G(8,0)→G'(0,-8)

Answer: the coordinates of vertices of quadrilateral D′E′F′G′ are D'(4,2), E'(7,-4), F'(3,-10), G'(0,-8).

8 0
3 years ago
(30 points)
Pani-rosa [81]

The vertices of the triangle are the points where any pair of lines intersect.

We start by setting up the system

\begin{cases}y=-x+2\\y=2x-1 \end{cases} \iff -x+2=2x-1 \iff 3x=3 \iff x=1

Using one of the two equations we can derive the correspondent y value:

f(x)=-x+2 \implies f(1)=-1+2 = 1

So, one vertex is (1, 1)

We choose the other two pairs of lines to find the other vertices:

\begin{cases}y=-x+2\\y=x-2 \end{cases} \iff -x+2=x-2 \iff x=2 \implies y = 0

\begin{cases}y=x-2\\y=2x-1 \end{cases} \iff x-2=2x-1 \iff x=-1 \implies y=-3

So, the three vertices are (1, 1), (2, 0), (-1, -3).

8 0
3 years ago
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