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3 years ago

Solve the compound inequality 10 + x < 20 and 4x > -24

Mathematics

1 answer:

kotykmax [81]3 years ago

6 0

Answer:

Step-by-step explanation:

1.) move all terms that are not x to the right side.of the inequalities.

10+x≤20 4x≥-24

-10 -10 4 4

x≤10 x≥-6

2.) combine the two equations to make -6≤x≤10

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The coefficient of x^ky^n-k in the expression of (x+y)^n equals (n-k/k) true or false

gulaghasi [49]

Answer:

False

Step-by-step explanation:

The given statement is:

The coefficient of x^ky^n-k in the expression of (x+y)^n equals (n-k/k)

This is a false statement

Reason:

When we do expansion of (x+y)^n by binomial theorem we get the following solution:

(x+y)^n = nCk x^k y^n-k

This shows that the coefficient of x^ky^n-k is nCk which is equivalent to n!/(n-k)! k!

Therefore it is a false statement....

3 0

3 years ago

2. The length of XZ is 28 units. If XY = 2x + 2 and YZ = 9x – 7, what are the lengths of XY and

Novosadov [1.4K]

Answer:

XY = 8 and YZ = 20

Step-by-step explanation:

If XY and YZ are on the one line, we can write

XY + YZ = 28

(2x+2) + (9x - 7) = 28

2x+2 + 9x - 7 = 28

11x - 5 = 28

11x = 33

x = 3

XY = 2x+2 = 2*3 + 2 = 8

YZ = 9x - 7 = 9*3 - 7 = 27 - 7 = 20

8 0

3 years ago

Identify the graph of the equation y = 2x2 − 2x + 1.

Schach [20]

Answer:

im pretty sure it's c

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Complete the table of values

Agata [3.3K]

Both problems give you a function in the second column and the x-values. To find out the values of a through f, you need to plug in those x-values into the function and simplify!

You need to know three exponent rules to simplify these expressions:
1) The negative exponent rule says that when a base has a negative exponent, flip the base onto the other side of the fraction to make it into a positive exponent. For example, $3^{-2} =
\frac{1}{3^{2} }$ .
2) Raising a fraction to a power is the same as separately raising the numerator and denominator to that power. For example, $(\frac{3}{4}) ^{3} = \frac{ 3^{3} }{4^{3} }$ .
3) The zero exponent rule says that any number raised to zero is 1. For example, $3^{0} = 1$ .


Back to the Problem:
Problem 1
The x-values are in the left column. The title of the right column tells you that the function is $y = 4^{-x}$ . The x-values are:
1) x = 0
Plug this into $y = 4^{-x}$ to find letter a:
$y = 4^{-x}\\
y = 4^{-0}\\
y = 4^{0}\\
y = 1$

2) x = 2
Plug this into $y = 4^{-x}$ to find letter b:
$y = 4^{-x}\\ 
y = 4^{-2}\\ 
y = \frac{1}{4^{2}} \\ 
y= \frac{1}{16}$

3) x = 4
Plug this into $y = 4^{-x}$ to find letter c:
$y = 4^{-x}\\ 
y = 4^{-4}\\ 
y = \frac{1}{4^{4}} \\ 
y= \frac{1}{256}$


Problem 2
The x-values are in the left column. The title of the right column tells you that the function is $y = (\frac{2}{3})^x$ . The x-values are:
1) x = 0
Plug this into $y = (\frac{2}{3})^x$ to find letter d:
$y = (\frac{2}{3})^x\\
y = (\frac{2}{3})^0\\
y = 1$

2) x = 2
Plug this into $y = (\frac{2}{3})^x$ to find letter e:
$y = (\frac{2}{3})^x\\ y = (\frac{2}{3})^2\\ y = \frac{2^2}{3^2}\\
y = \frac{4}{9}$

3) x = 4
Plug this into $y = (\frac{2}{3})^x$ to find letter f:
$y = (\frac{2}{3})^x\\ y = (\frac{2}{3})^4\\ y = \frac{2^4}{3^4}\\ y = \frac{16}{81}$

-------

Answers:
a = 1
b = $\frac{1}{16}$ 
c = $\frac{1}{256}$
d = 1
e = $\frac{4}{9}$
f = $\frac{16}{81}$

5 0

3 years ago

Ali had his car repaired at Ace Auto. He was charged AED 50 per hour of labor plus AED 150 for parts. His total bill for the rep

AnnZ [28]

Step-by-step explanation:

x = hours Ali was charged for

150 + 50 x = 375

- 150 -150

50x = 225

÷ 50. ÷50

x = 4.5 hours

6 0

3 years ago