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Lady_Fox [76]
3 years ago
15

If you are given an unknown liquid that is 1.0 L and has the mass of 500 grams which of the substance would it be. Distilled Wat

er Density= 1.0g/cm^3, Propane density 0.494 g/cm^3, Salt Water density 1.025 g/cm^3 or Liquid Gold 17.31 g/cm^3?
Chemistry
1 answer:
kodGreya [7K]3 years ago
8 0
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Which would have the highest first ionization energy?
LekaFEV [45]

Answer:

Thus, helium has the largest first ionization energy, while francium has one of the lowest.

7 0
2 years ago
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What is the gram formula mass of Ca3(PO4)2
Georgia [21]
Mass Molar of Ca_{3} (PO_4)_2
Ca = 3*40 = 120 amu
P = 2*31= 62 amu
O = (16*4)*2 = 64*2 = 128 amu
--------------------------------------
Mass Molar of Ca_{3} (PO_4)_2 = 120 + 62 + 128 = 310 g/mol

Therefore: <span>What is the gram formula mass of Ca3(PO4)2 ?
</span>Answer: 310 grams
6 0
3 years ago
A balloon starts out with a volume of 1.3 l at 115.3 kpa. if the temperature is held constant, what would the new volume be if t
Anna35 [415]

The new volume be if the pressure inside the balloon was reduced to 58kpa is 2.58 L.

<h3>What is ideal gas equation?</h3>

Ideal gas equation PV=nRT gives idea about the behavior of gases at different conditions and for this question the equation becomes:

P₁V₁ = P₂V₂, where

P₁ = initial pressure = 115.3 kpa

V₁ = initial volume = 1.3 L

P₂ = final pressure = 58 kpa

V₂ = final volume = ?

On putting all these values in the above equation, we get

V₂ = (115.3)(1.3) / (58) = 2.58 L

Hence resultant volume of gas is 2.58 L.

To know more about ideal gas equation, visit the below link:

brainly.com/question/18909295

#SPJ1

8 0
2 years ago
Calculate the numbers of mL in 0.603 L
Artist 52 [7]

Answer:

603 mL

Explanation:

A milliliter is a unit of volume equal to 1/1000th of a liter. It is the same as a cubic centimeter.

6 0
3 years ago
By pipet, 11.00 mL of a 0.823 MM stock solution of potassium permanganate (KMnO4) was transferred to a 50.00-mL volumetric flask
tangare [24]

Answer:

1) 0.18106 M is the molarity of the resulting solution.

2) 0.823 Molar is the molarity of the solution.

Explanation:

1) Volume of stock solution = V_1=11.00 mL

Concentration of stock solution = M_1=0.823 M

Volume of stock solution after dilution = V_2=50.00 mL

Concentration of stock solution after dilution = M_2=?

M_1V_1=M_2V_2 ( dilution )

M_2=\frac{0.823 M\times 11.00 mL}{50 ,00 mL}=0.18106 M

0.18106 M is the molarity of the resulting solution.

2)

Molarity of the solution is the moles of compound in 1 Liter solutions.

Molarity=\frac{\text{Mass of compound}}{\text{Molar mas of compound}\times Volume (L)}

Mass of potassium permanganate = 13.0 g

Molar mass of potassium permangante = 158 g/mol

Volume of the solution = 100.00 mL = 0.100  L ( 1 mL=0.001 L)

Molarity=\frac{13.0 g}{158 g/mol\times 0.100 L}=0.823 mol/L

0.823 Molar is the molarity of the solution.

6 0
2 years ago
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