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Lady_Fox [76]
3 years ago
15

If you are given an unknown liquid that is 1.0 L and has the mass of 500 grams which of the substance would it be. Distilled Wat

er Density= 1.0g/cm^3, Propane density 0.494 g/cm^3, Salt Water density 1.025 g/cm^3 or Liquid Gold 17.31 g/cm^3?
Chemistry
1 answer:
kodGreya [7K]3 years ago
8 0
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A 10.00 mL sample of a solution containing formic acid (a weak acid) was placed in a 25 mL volumetric flask and diluted to the m
Eddi Din [679]

Answer:

Molarity: 0.522M

Percentage by mass: 2.36 (w/w) %

Explanation:

Formic acid, HCOOH reacts with NaOH as follows:

HCOOH + NaOH → NaCOOH + H₂O

To solve this question we must find the moles of NaOH added = Moles formic acid. Taken into account the dilution that was made we can find the moles -And molarity of formic acid and its percentage by mass as follows:

<em>Moles NaOH = Moles HCOOH:</em>

0.01580L * (0.1322mol / L) =0.002089 moles HCOOH

<em>Moles in the original solution:</em>

0.002089 moles HCOOH * (25mL / 10mL) = 0.005222 moles HCOOH

<em>Molarity of the solution:</em>

0.005222 moles HCOOH / 0.01000L =

<h3>0.522M</h3>

<em>Mass HCOOH in 1L -Molar mass: 46.03g/mol-</em>

0.522moles * (46.03g / mol) = 24.04g HCOOH

<em>Mass solution:</em>

1L = 1000mL * (1.02g / mL) = 1020g solution

<em>Mass percent:</em>

24.04g HCOOH / 1020g solution * 100

2.36 (w/w) %

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What I came up with was D equaling out to be 42

Explanation:

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B. 2.4 x 103 = 247.2

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