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cupoosta [38]
2 years ago
15

How many moles of gas are in a 30 liter compressed air tank if the

Chemistry
2 answers:
motikmotik2 years ago
7 0
I think it’s is, B, not sure though
sp2606 [1]2 years ago
4 0

Answer:

B

Explanation:

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omplete the relationship between ph and pka for each of the following atomic view pictures of a buffered solution.
Yakvenalex [24]

The relationship between pH and pKa of buffer solution in given atomic view:

In figure I  pH= pKa  ( since [HA] =[A-] )

In figure II pH > pKa ( since [A-] > [HA] )

In figure III pH < pKa ( since [A-] < [HA] )

The pH and pKa are related by the Henderson-Hasselbalch equation. It should not be used for concentrated solutions, extremely low pH acids, or extremely high pH bases because it is simply an approximation.

pH =  pKa + log(conjugate base/weak acid).

pH equals pKa plus log ([A-] / [HA]).

pH is determined by dividing the weak acid concentration by the log of the conjugate base concentration and the pKa value.

About halfway to the equivalence point:

pH = pKa

It's important to note that this equation is familiar with the connection because it is sometimes written for the Ka value rather than the pKa value.

pKa = – log Ka

Hence, value of pH depend on relative concentration of [A-]  and HA]

To know more about Ka.

brainly.com/question/16035742

#SPJ4

5 0
1 year ago
An analogy makes a comparison between objects based on their similar qualities. Cassidy wanted to create an analogy for the moti
cricket20 [7]
B
atoms in a solid can move very little because of how compact they are
in a liquid atoms move a little more freely
in a gas atoms are bouncing fast as they are very spaced out
7 0
3 years ago
Read 2 more answers
T. Svedberg measured the molecular weight of carbonyl hemoglobin by velocity centrifugation. In this experiment, 0.96 g of prote
Natalija [7]

Answer:

The molecular weight is 77.7 kg/mol

Explanation:

The molecular mass of hemoglobin is equal to:

M=\frac{RTs}{D(1-Vp)}

Where

R = molar gas constant = 8.315 J/K mol

p = density = 0.998 g/mL

V = specific volume = 0.755 mL/g

s = sedimentation rate = ?

D = diffusion rate = 7x10⁻¹¹m²/s

T = temperature = 303 K

The sedimentation rate is equal to:

s=\frac{1}{w^{2}t } ln(\frac{x_{b,t} }{x_{b,0} } )

Where

w = angular velocity = 39300 rpm = 246929.18 rad/min

xb,30 = boundary midpoint distance at 30 min = 4.525 + 0.074 cm

t = time = 30 min

xb,0 = boundary midpoint distante at 0 min = 4.525 cm

s=\frac{1}{246929.18^{2}*30 } ln(\frac{4.525+0.074}{4.525} )=8.87x10^{-13} min=5.32x10^{-13} s

The molecular weight is:

M=\frac{8.315*303*5.32x10^{-13} }{7x10^{-11}*(1-(0.755*0.998)) } =77.7kg/mol

5 0
3 years ago
Which object has the greatest K.E.?"<br> top of a hill<br> bottom of a hill<br> middle of a hill
Licemer1 [7]

Answer: the answer is A

Explanation:

The answers is A

8 0
3 years ago
Read 2 more answers
How many atoms are found in 12.0 grams of Helium?
Allisa [31]
<span>Each mole contains Avagodro's number of atoms i.e. 6.023x10^23, so

3 moles x 6.023x10^23 atoms/mole = 18.069x10^23 atoms = 1.8x19^24 atoms </span>
3 0
3 years ago
Read 2 more answers
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