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3 years ago

This is another word for microorganism.

Chemistry

2 answers:

nadezda [96]3 years ago

7 0

Answer:

The another word for microorganism is microbe

ale4655 [162]3 years ago

5 0

Answer:

Option C

Explanation:

Microbe..... Microorganisms are also known as microbes.

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vova2212 [387]

:1because they release large amount of haet per effective mass when burned

Addition Einstein eqn Energy=mass×freq

2 Small byproduct is smokes and ashes

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3 years ago

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A solution used to chlorinate a home swimming pool contains 7% chlorine by mass. An ideal chlorine level for the pool is one par

deff fn [24]

Answer:

Volume of chlorine = 61.943 mL

Explanation:

Given:

Volume of the water in the Pool = 18,000 gal

also,

1 gal = 3785.412 mL

thus,

Volume of water in pool = 18,000 × 3785.412 = 68,137,470 mL

Density of water = 1.00 g/mL

Therefore,

The mass of water in the pool = Volume × Density

The mass of water in the pool = 68,137,470 mL × 1.00 g/mL = 68,137,470 g

in terms of million = $\frac{\textup{68,137,470}}{\textup{ 1,000,000}}$

= 68.13747 g

also,

1 g of chlorine is present per million grams of water

thus,

chlorine present is 68.13747 g

Now,

volume = $\frac{\textup{Mass}}{\textup{Density}}$

Volume of chlorine = $\frac{\textup{68.13747 g}}{\textup{1.10 g/mL}}$

Volume of chlorine = 61.943 mL

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4 years ago

( Cooking Popcorn using a mircowave Burning yourself by touching burning water the handle of a pot becoming to hot to touch as i

mihalych1998 [28]

Conduction - touching hot pot
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3 years ago

Balance equation Al(s)+__CuSO4(aq) = ____Al2(SO4)3(aq)+____Cu(s)

Leokris [45]

2Al +3CuSO4=Al2 (SO4)3+3Cu.

is the balanced equation.

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4 years ago

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The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula: E = R_y/n^2 In this equation R_y stands

Katarina [22]

Answer:

The wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron for the given energy levels is $5.23\times 10^{-5} m$

Explanation:

Given :

The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula:

$E=\frac{R_y}{n^2}$

$R_y=2.18\times 10^{-18} J$ = Rydberg energy

n = principal quantum number of the orbital

Energy of 11th orbit = $E_{11}$

$E_{11}=\frac{2.18\times 10^{-18} J}{11^2}=1.80\times 10^{-20} J$

Energy of 10th orbit = $E_{10}$

$E_{10}=\frac{2.18\times 10^{-18} J}{10^2}=2.18\times 10^{-20} J$

Energy difference between both the levels will corresponds to the energy of the wavelength of the line which can be calculated by using Planck's equation.

$E'=E_{10}-E_{11}=2.18\times 10^{-20} J-1.80\times 10^{-20} J$

$=E'=0.38\times 10^{-20} J$

$\lambda =\frac{hc}{E'}$ (Planck's' equation)

$\lambda = \frac{6.626\times 10^{-34} Js\times 3\times 10^8 m/s}{0.38\times 10^{-20} J}$

$\lambda = 5.2310\times 10^{-5} m\approx 5.23\times 10^{-5} m$

The wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron for the given energy levels is $5.23\times 10^{-5} m$

3 0

3 years ago