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djverab [1.8K]
2 years ago
13

Summarize the rules for the allowable values of the four quantum numbers of an electron in an atom.

Chemistry
1 answer:
vodomira [7]2 years ago
5 0

Answer : Rules for the allowable values of the four quantum numbers are:

  • 'n' must be positive integer that means n > 0
  • The value of 'l' must be from 0 to (n-1)
  • The value of 'ml' must be from (-l\text{ to }+l)
  • The value of 'ms' must be +\frac{1}{2} or -\frac{1}{2}

Explanation:

Principle Quantum Numbers : It describes the size of the orbital. It is represented by n. n = 1,2,3,4....

Azimuthal Quantum Number : It describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For l = 0,1,2,3... the orbitals are s, p, d, f...

Magnetic Quantum Number : It describes the orientation of the orbitals. It is represented as m_l. The value of this quantum number ranges from (-l\text{ to }+l). When l = 2, the value of

Spin Quantum number : It describes the direction of electron spin. This is represented as m_s. The value of this is +\frac{1}{2} for upward spin and -\frac{1}{2} for downward spin.

Rules for the allowable values of the four quantum numbers are:

  • 'n' must be positive integer that means n > 0
  • The value of 'l' must be from 0 to (n-1)
  • The value of 'ml' must be from (-l\text{ to }+l)
  • The value of 'ms' must be +\frac{1}{2} or -\frac{1}{2}
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Explanation:

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4

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Consider the hypothetical reaction 4A + 3B → C + 2D Over an interval of 3.00 s the average rate of change of the concentration o
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Answer:

Final concentration of C at the end of the interval of 3s if its initial concentration was 3.0 M, is 3.06 M and if the initial concentration was 3.960 M, the concentration at the end of the interval is 4.02 M

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4 moles of A gives 1 mole of C

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If the initial concentration of C was 3 M, the new concentration of C would be (3 + 0.06) = 3.06 M.

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