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djverab [1.8K]
2 years ago
13

Summarize the rules for the allowable values of the four quantum numbers of an electron in an atom.

Chemistry
1 answer:
vodomira [7]2 years ago
5 0

Answer : Rules for the allowable values of the four quantum numbers are:

  • 'n' must be positive integer that means n > 0
  • The value of 'l' must be from 0 to (n-1)
  • The value of 'ml' must be from (-l\text{ to }+l)
  • The value of 'ms' must be +\frac{1}{2} or -\frac{1}{2}

Explanation:

Principle Quantum Numbers : It describes the size of the orbital. It is represented by n. n = 1,2,3,4....

Azimuthal Quantum Number : It describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For l = 0,1,2,3... the orbitals are s, p, d, f...

Magnetic Quantum Number : It describes the orientation of the orbitals. It is represented as m_l. The value of this quantum number ranges from (-l\text{ to }+l). When l = 2, the value of

Spin Quantum number : It describes the direction of electron spin. This is represented as m_s. The value of this is +\frac{1}{2} for upward spin and -\frac{1}{2} for downward spin.

Rules for the allowable values of the four quantum numbers are:

  • 'n' must be positive integer that means n > 0
  • The value of 'l' must be from 0 to (n-1)
  • The value of 'ml' must be from (-l\text{ to }+l)
  • The value of 'ms' must be +\frac{1}{2} or -\frac{1}{2}
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Answer:

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If the value for ΔS is postive, and the value for ΔH is negative, thr reaction will be
dmitriy555 [2]

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1 year ago
1. If a solution containing 48.99 g of mercury(II) perchlorate is allowed to react completely with a solution containing 8.564 g
Vitek1552 [10]

1. Chemical eqn:

Hg(ClO4)2 + Na2S -> HgS + 2NaClO4

mercury perchlorate has a molar mass of 399.5g/mol (1d.p) and for Na2S it is 78.0g/mol (1d.p.)

no. of moles of mercury perchlorate= 48.99÷399.5= 0.12263mol(5s.f.)

no. of moles of Na2S= 8.564÷78.0= 0.10979mol ( 5s.f.)

so no. of moles of Hg(ClO4)2/ no. of moles of Na2S= 1/1 according to the eqn

so no. of moles of Hg(ClO4)2 needed if all Na2S is used up is 1/1×0.10979= 0.10979 mols

since no. of moles of mercury perchlorate needed < no. of moles of it provided, it is in excess and Na2S is the limiting factor.

since HgS is a solid and NaClO4 is aqueous, solid ppt formed will only be HgS.

no. of moles of HgS/ no. of moles of NaClO4= 1/1

no. of moles of HgS produced= 0.10979mols

molar mass of HgS= 232.7g/mol 1d.p.

grams of solid produced= 232.7×0.10979= 25.5g (3s.f.)

2. reactant in excess is Hg(ClO4)2,

no. of excess moles= 0.12263-0.10979= 0.01284mols

grams of excess reactant= 0.01284×399.5= 5.13g (3s.f.)

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