Ask question

Ask question

All categories

2 years ago

10

Calculate the number of grams of sulfuric acid in 1 gallon of battery acid if the solution has a density of 1.25 g/mL and is 37.

4 % sulfuric acid by mass.

1 answer:

loris [4]2 years ago

4 0

Answer:

break it down and just put the numbers

Explanation:

You might be interested in

20g of butanedioic acid were shaken with a mixture of 100 cm3 ether and 100 cm3 water at 298K. After titration with standard sod

zlopas [31]

Answer:

I'm Not Good At Chemistry.

Explanation: It's Hard.

8 0

2 years ago

How are distant regions of the universe similar to space near earth

Sergeu [11.5K]

<span>The distant regions of the Universe look older than the space near the Earth. The more distant are, the older is. But the information we can have is lesser due to the distance.</span>

3 0

2 years ago

A 44% wt/wt solution of H2SO4 has a density of 1.343g/ml. What mass of H2SO4 is 60ml of this solution?

horsena [70]

<u>Answer:</u> The mass of sulfuric acid present in 60 mL of solution is 34.1 grams

<u>Explanation:</u>

We are given:

44 % (m/m) solution of sulfuric acid. This means that 44 grams of sulfuric acid is present in 100 grams of solution.

To calculate volume of a substance, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of solution = 1.343 g/mL

Mass of solution = 100 g

Putting values in above equation, we get:

$1.343g/mL=\frac{100g}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{100g}{1.343g/mL}=77.46mL$

To calculate the mass of sulfuric acid present in 60 mL of solution, we use unitary method:

In 77.46 mL of solution, mass of sulfuric acid present is 44 g

So, in 60 mL of solution, mass of sulfuric acid present will be = $\frac{44g}{77.46mL}\times 60mL=34.1g$

Hence, the mass of sulfuric acid present in 60 mL of solution is 34.1 grams

3 0

3 years ago

What is the percent of O in CO2

zmey [24]

72.71 . simple google search, you shouldnt waste points

5 0

3 years ago

Read 2 more answers

Carbon dioxide dissolves in water to form carbonic acid, which is primarily dissolved CO2. Dissolved CO2 satisfies the equilibri

Dvinal [7]

C = pK
<span>C = 4.4E-4*0.032 = about 1.41E-5 </span>

<span>H2CO3 ==> H^+ + HCO3^- </span>

<span>k1 = (H^+)(HCO3^-)/(H2CO3) </span>
<span>(H^+)= (HCO3^-) = x </span>
<span>(H2CO3) = 1.41E-5 </span>
<span>Solve for x = (H^+) and convert to pH. </span>

6 0

3 years ago