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Natalija [7]
2 years ago
12

Zachary adds 9.7 g to 1.114 g. How many significant figures should his answer have?

Chemistry
1 answer:
makvit [3.9K]2 years ago
5 0
Always use least amount of sig figs possible. So this 9.7 would be (answer): 2 sig figs
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Whag is the answer. please i need help​
icang [17]

Answer:

First option

Explanation:

Students 1 and 2 have precise measures yet is is not accurate since they measure around 5.

5 0
3 years ago
365g MnSiO3 = ___ mol
trapecia [35]
2.79 mol of MnSiO3

This will be very close but may not be exactly accurate, depending on what your periodic table says.
7 0
2 years ago
3 What is the number located in the top right hand corner of the atomic symbol of an ion with 16 protons, 17 neutrons and 14 ele
siniylev [52]

The number located in the top right corner of the ion is +2

An ion is an atom or group of atoms which possess an electric charge.

The charge on an ion can be obtained by using the following formula:

<h3>Charge = Proton – Electron </h3>

With the above formula, we can obtain the charge of the ion given in the question above as illustrated below:

Proton = 16

Neutron = 17

Electron = 14

<h3>Charge =? </h3>

Charge = Proton – Electron

Charge = 16 – 14

<h3>Charge = +2</h3>

Therefore, the charge on the ion is +2

Learn more: brainly.com/question/3428265

3 0
2 years ago
Enter your answer in the provided box. an aqueous solution containing 10 g of an optically pure substance was diluted to 500 ml
sladkih [1.3K]

Answer:

[α] = -77.5° / \frac{\textup{dm-g}}{\textup{mL}}

Explanation:

Given;

Mass of optically pure substance in the solution = 10 g

Volume of water = 500 mL

Length of the polarimeter, l = 20 cm = 20 × 0.1 dm = 2 dm

measured rotation = - 3.10°

Now,

The specific rotation ( [α] ) is given as:

[α] = \frac{\alpha}{c\times l}

here,

α is the measured rotation = -3.10°

c is the concentration

or

c = \frac{\textup{Mass of optically pure substance in the solution}}{\textup{Volume of water}}

or

c =  \frac{10}{500}

or

c = 0.02 g/mL

on substituting the values, we get

[α] = \frac{-3.10^o}{0.02\times2}

or

[α] = -77.5° / \frac{\textup{dm-g}}{\textup{mL}}

7 0
3 years ago
In the titration between potassium iodate and the sodium thiosulfate solution, if the titration is not performed immediately aft
N76 [4]

Answer:

The calculated concentration of sodium thiosulphate solution will be less than the actual value.

Explanation:

When IO3^2- solution is added to KI solution, I2 gas is released ,then sulphuric acid is now added to facilitate reduction. In order to prevent the escape of iodine (I2) gas ,the solution must immediately be titrated with thiosulphate.

If the solution is not immediately titrated with thiosulphate, the concentration of iodine available in the system decreases. When this occurs, it will also cause a decrease in the amount of iodine available to react with thiosulphate thus decreasing the concentration of thiosulphate obtained from calculation

5 0
3 years ago
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