D
Nuclear reaction involves the nuclei of atoms. The nucleus can either split (as is the case with fission) of fuse as is the case with nuclear fusion. Remember the main particles in the nucleus are protons and neutrons.
Explanation:
In nuclear fission, atomic nuclei split into lighter atoms through loss of protons and neutrons (such as through loos of a beta particles - 2 protons and 2 neutrons). In the case of fusion, two atomic nuclei fuse under pressure (hence adding neutrons and protons) to create heavier atoms (2 hydrogens can fuse to form a helium). Electrons are not involved in nuclear reactions. Electrons are mainly involved in chemical reactions.
Learn More:
For more on nuclear fission and fusion check out;
brainly.com/question/913303
brainly.com/question/10245756
brainly.com/question/11354515
brainly.com/question/2005577
brainly.com/question/2005577
#LearnWithBrainly
Precipitation hope this helped you
You would need 8.1 <span>moles of LiOH</span>
Answer:
pH ≅ 4.80
Explanation:
Given that:
the volume of HN₃ = 25 mL = 0.025 L
Molarity of HN₃ = 0.150 M
number of moles of HN₃ = 0.025 × 0.150
number of moles of HN₃ = 0.00375 mol
Molarity of NaOH = 0.150 M
the volume of NaOH = 13.3 mL = 0.0133
number of moles of NaOH = 0.0133× 0.150
number of moles of NaOH = 0.001995 mol
The chemical equation for the reaction of this process can be written as:

1 mole of hydrazoic acid react with 1 mole of hydroxide to give nitride ion and water
thus the new number of moles of HN₃ = 0.00375 - 0.001995 = 0.001755 mol
Total volume used in the reaction = 0.025 + 0.0133 = 0.0383 L
Concentration of
=
= 0.0458 M
Concentration of
=
= 0.0521 M
GIven that :
Ka = 
Thus; it's pKa = 4.72




pH ≅ 4.80