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lina2011 [118]
2 years ago
12

What is the molarity of a solution that is made by adding 57.3 g of MgO to 500.0 mL of solutions

Chemistry
1 answer:
goblinko [34]2 years ago
6 0

Answer:

The answer to your question is 2.84 M

Explanation:

Data

mass of MgO = 57.3 g

volume of the solution = 500 ml

Process

1.- Calculate the molar mass of MgO

MgO = 24.3 + 16 = 40.3 g

2.- Calculate the moles of MgO

                 40.3 g MgO ----------------- 1 mol

                  57.3 g MgO -----------------  x

                          x = (57.3 x 1) / 40.3

                          x = 1.42 moles

3.- Calculate the Molarity

Molarity = moles / volume (l)

Volume = 0.5 liters

-Substitution

Molarity = 1.42 / 0.5

-Result

Molarity = 2.84

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Answer:

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Explanation:

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Answer:

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Explanation:

Volume is the amount of space taken up or occupied by an object.

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A water treatment plant receives the source water with an average Ca2+ concentration of 46.9 mg/L and Mg2+ concentration of 14.8
Veronika [31]

Answer:

42,650 kg of calcium carbonate will be produced everyday.

13,600.5 kg of magnesium hydroxide will be produced everyday.

Explanation:

Concentration of calcium ions = 46.9 mg/L

Concentration of magnesium ions = 14.8  mg/L

Volume of solution treated everyday , V= 80 million gal

= 80\times 10^6 gal=4.546\times 80\time 10^6 L=3.637\times 10^8 L

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=  1.706\times 10^{10} mg

1 mg = 0.001 g

1.706\times 10^{7} g

Moles of calcium ions = \frac{1.706\times 10^{7} g}{40 g/mol}=426,500 mol

From 1 mole of calcium ion 1mol of carbonate is formed . then from 426,500 moles of calcium ion will form :

\frac{1}{1}\times 426,500 mol=426,500 mol of calcium carbonate

Mass of 426,500 moles of calcium carbonate:

426,500 mol × 100 g/mol  = 42,650,000 g = 42,650 kg

Mass of  magnesium ion in V = 14.8 mg/L\times 3.637\times 10^8 L

= 5.382\times 10^{9} mg

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Moles of magnesium ions = \frac{5.382\times 10^{6} g}{24 g/mol}=224,250 mol

From 1 mole of magnesium ion 1 mol of magnesium hydroxide is formed . then from 224,250 moles of magnesium ion will form :

\frac{1}{1}\times 224,250 mol=224,250 mol of magnesium hydroxide

Mass of 224,250 moles of magnesium hydroxide:

224,250 mol × 58 g/mol  = 13,006,500 g = 13,006.5 kg

42,650 kg of calcium carbonate will be produced everyday.

13,600.5 kg of magnesium hydroxide will be produced everyday.

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3 years ago
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Answer:

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