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lina2011 [118]
3 years ago
12

What is the molarity of a solution that is made by adding 57.3 g of MgO to 500.0 mL of solutions

Chemistry
1 answer:
goblinko [34]3 years ago
6 0

Answer:

The answer to your question is 2.84 M

Explanation:

Data

mass of MgO = 57.3 g

volume of the solution = 500 ml

Process

1.- Calculate the molar mass of MgO

MgO = 24.3 + 16 = 40.3 g

2.- Calculate the moles of MgO

                 40.3 g MgO ----------------- 1 mol

                  57.3 g MgO -----------------  x

                          x = (57.3 x 1) / 40.3

                          x = 1.42 moles

3.- Calculate the Molarity

Molarity = moles / volume (l)

Volume = 0.5 liters

-Substitution

Molarity = 1.42 / 0.5

-Result

Molarity = 2.84

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Aluminum–lithium (Al–Li) alloys have been developed by the aircraft industry to reduce the weight and improve the performance of
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Answer:

6.54% is the required concentration of lithium in an alloy (Al–Li).

Explanation:

Suppose 100 grams of an alloy of aluminium and lithium.

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v_2=\frac{y}{d_2}

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Solving [1] and [2] :

we get :

x = 93.46 g

y = 6.54 g

Concentration of Li (in wt%) that is required:

Li\%=\frac{6.54 g}{100 g}\times 100=6.54\%

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