Answer:
Option d. 2615.0g
Explanation:
Let M1, M2, and M3 represent the masses of the three different samples
M1 = 0.1568934 kg = 156.8934g
M2 = 1.215mg = 1.215x10^-3 = 0.001215g
M3 = 2458.1g
Total Mass = M1 + M2 + M3
Total Mass = 156.8934 + 0.001215 + 2458.1
Total Mass = 2614.994651g
Total Mass = 2615.0g
Answer:
to determine of it is a solid liquid or gas.
Explanation:
The melting point is the temperature at which a substance converts from a solid state to a liquid state.
The molarity of the stock solution is 1.25 M.
<u>Explanation:</u>
We have to find the molarity of the stock solution using the law of volumetric analysis as,
V1M1 = V2M2
V1 = 150 ml
M1 = 0.5 M
V2 = 60 ml
M2 = ?
The above equation can be rearranged to get M2 as,
M2 = ![$\frac{V1M1}{V2}](https://tex.z-dn.net/?f=%24%5Cfrac%7BV1M1%7D%7BV2%7D)
Plugin the values as,
M2 = ![$\frac{150 \times 0.5}{60}](https://tex.z-dn.net/?f=%24%5Cfrac%7B150%20%5Ctimes%200.5%7D%7B60%7D)
= 1.25 M
So the molarity of the stock solution is 1.25 M.
<u>Answer:</u> The percentage abundance of
and
isotopes are 77.5% and 22.5% respectively.
<u>Explanation:</u>
Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.
Formula used to calculate average atomic mass follows:
.....(1)
Let the fractional abundance of
isotope be 'x'. So, fractional abundance of
isotope will be '1 - x'
- <u>For
isotope:</u>
Mass of
isotope = 35 amu
Fractional abundance of
isotope = x
- <u>For
isotope:</u>
Mass of
isotope = 37 amu
Fractional abundance of
isotope = 1 - x
Average atomic mass of chlorine = 35.45 amu
Putting values in equation 1, we get:
![35.45=[(35\times x)+(37\times (1-x))]\\\\x=0.775](https://tex.z-dn.net/?f=35.45%3D%5B%2835%5Ctimes%20x%29%2B%2837%5Ctimes%20%281-x%29%29%5D%5C%5C%5C%5Cx%3D0.775)
Percentage abundance of
isotope = ![0.775\times 100=77.5\%](https://tex.z-dn.net/?f=0.775%5Ctimes%20100%3D77.5%5C%25)
Percentage abundance of
isotope = ![(1-0.775)=0.225\times 100=22.5\%](https://tex.z-dn.net/?f=%281-0.775%29%3D0.225%5Ctimes%20100%3D22.5%5C%25)
Hence, the percentage abundance of
and
isotopes are 77.5% and 22.5% respectively.