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3 years ago

Does anyone know this one???

Chemistry

1 answer:

iren2701 [21]3 years ago

7 0

Answer:

peep peep bonst stonst with a pormp pomp po beeet teet teetily

Explanation:

corncobpipe accident

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I NEED HELP. PLEASE HELP ME!!!!

lidiya [134]

Answer:

We have to add 2RbNO3 (option A)

10 Rb +2RbNO3 → 6 Rb2O + N2

Explanation:

Step 1: The equation:

10 Rb + _____ —> 6 Rb2O + N2

Step 2: Balancing the equation

On the right side we have 6x2 = 12 Rb atoms.

On the left side we have 10x Rb

This means we need to add 2x Rb on the left side.

On the right side we have 2x N, On the left side 0x N.

This means we need to add 2x N on the left side.

On the right side we jave 6x O, on the left side we have 0x O.

This means we need to add 6x O on the left side.

We add this by adding RbNO3

This means we have to add 2x RbNO3 (option A)

10 Rb +2RbNO3 → 6 Rb2O + N2

5 0

3 years ago

Jaką maksymalną ilość gramów azotanu (V) potasu można rozpuscic w 300g wody w temperaturze 90 C

olga2289 [7]

Answer:

609g

Explanation:

The translated question is:

What maximum amount of grams of potassium nitrate (V) can be dissolved in 300g of water at 90 °C

<h2>Solution</h2>

To answer the question you need to consultate the solubiity information for potassium nitrate (V), KNO₃.

The attached table contains the solutibility table for KNO₃ at different temperatures.

At 90ºC it is 203g / 100g water.

Then, to calculate the maximum amount of grams of potassium nitrate (V) that can be dissolved in 300g of water at 90 °C, just multiply by the amount of water:

203g / 100g water × 300 g water = 609g ← answer

6 0

3 years ago

Energy flows from colder objects to warmer objects. is it true or false?

mixas84 [53]

Answer:

true. j

Explanation:

I think its true

7 0

3 years ago

Read 2 more answers

The Moon’s appearance changes during its ________ around Earth. These changes are called ____________________.

Daniel [21]

Answer:

The Moon’s appearance changes during its orbit around Earth. These changes are called phases.

Explanation:

4 0

3 years ago

Ethanol, C2H6O, is most often blended with gasoline - usually as a 10 percent mix - to create a fuel called gasohol. Ethanol is

ch4aika [34]

Answer:

4054 kcal of heat is released during complete combustion of 354 g of octane.

Explanation:

Heat of combustion of 1 mol of octane is $1.308\times 10^{3}$ kcal

Molar mass of octane = 114.23 g/mol

We know, no. of moles = (mass)/(molar mass)

So, $1.308\times 10^{3}$ kcal of heat is released during complete combustion of 114.23 g of octane.

So, amount of heat is released during complete combustion of 354 g of octane = $(\frac{1.308\times 10^{3}}{114.23})\times 354$ kcal = 4054 kcal

Hence 4054 kcal of heat is released during complete combustion of 354 g of octane.

5 0

3 years ago