Answer:
A-bone cell, bone cell C-bone tissue, bone cell bone tissue, femur, skeleton, dog B-dog.
Explanation:
It is ordered from the smallest unit (tissue microstructure) to a tissue or organ that are considered macrotisular structures.
Explanation:
The reaction is as follows:
2Mg(s) + O2(g) ---> 2MgO(s)
and the researcher said that 32 g of MgO was produced.
Stoichiometry:
28 g Mg × (1 mol Mg/24.305 g Mg) = 1.15 mol Mg
15 g O2 × (1 mol O2/15.999 g O2) = 0.938 mol O2
1.15 mol Mg × (2 mol MgO/2 mol MgO) = 1.15 mol MgO
1.15 mol MgO × (40.3044 g MgO/1 mol MgO) = 46.6 g MgO
0.938 mol O2 × (2 mol MgO/1 mol O2) = 1.88 mol MgO
1.88 mol MgO × (40.3044 g MgO/1 mol MgO = 75.6 g MgO
Based on these numbers, the amount of product after the reaction is much less than expected so these results don't seem to support the law of conservation of matter.
The answer is a. H+ and H2O. For a half-reaction in acidic solutions, elements that are not hydrogen and oxygen are balanced first. Then we add H2O to balance oxygen atoms and we add H+ to balance the hydrogen atoms. We do the same steps for basic solutions, but we also add hydroxide ions OH- in the latter part.
Complete combustion of acetylene generated carbon dioxide and water. This can be represent by following reaction
2C2H2 + 5O2 → 4CO2 + 2H2O
(2 mole) (4 mole)
From the above balanced reaction, it can be seen that 2 mole of acetylene on complete combustion generates 4 moles of carbon dioxide
i.e. 2 mole of C2H2 ≡ 4 mole of CO2
∴ 1.3 mole of C2H2 ≡ (4 X 1.3)/2 = 2.6 mole of CO2
Now, 1 mole of CO2 = 44 g
∴ 2.6 mole of CO2 = (44 X 2.6) = 114.4 g
Thus, <span>114.4 grams of carbon dioxide are produced from the combustion of 1.3 moles of acetylene</span>
