Answer:
Below are some patterns in the charge for elements in each group.
Group 1 elements : 1 valence electron and form ions with charge +1
Group 2 elements : 2 valence electrons and form ions with charge + 2
Group 3 elements : 3 valence electrons and form ions with charge + 3(there are some exceptions as well)
Elements in groups 4 and 5 are unpredictable also the D block elements consist of multiple oxidation states..
Group 6 elements : 6 valence electrons, form ions with charge -2
Group 7 elements: 7 valence electrons, form ions with charge -1
The octet rule is being followed, the elements form either ionic bond or covalent bond to fulfill it.
eg: when a K atom forms a K+ ion, the ion has the same electron configuration as the noble gas Ar (argon).
When an O atom gains 2 electrons to form the O²⁻ ion, the ion has the same electron configuration as the noble gas Ne (neon).
Note: Boron (B) is in Group 3 but doesn't form ions.
It is perpendicular to both as the sidelines are parallel
I’m pretty sure you would have to divide 5 and 30 and you will get 0.16666666 but I would think it would be 6cm/s but I could be wrong and if it is I’m am truly sorry.
884 pounds of carbon dioxide are emitted in 400 litres.
What is a pound?
The pound is defined as the basic unit for weight in the Foot Pound Second (F.P.S) system and is equal to 16 ounces.
To convert a litre measurement to a pound measurement, multiply the volume by 2.204623 times the density of the ingredient or material. Thus, the volume in pounds is equal to the litres multiplied by 2.204623 times the density of the ingredient or material.
One litre of water weighs approximately 2.21 pounds.
So 400 liter = 400 liter x 2.21 pounds
= 884 pounds
Hence, 884 pounds of carbon dioxide are emitted in 400 litres.
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Answer:
Oxygen and Carbon are in the non-metal section. Both are in 2nd period while Carbon is in group 4A and Oxygen is in group 6A.
Oxygen has more valence electrons than carbon. I wish I could give you a more accurate explanation why on paper, but all you need to do is count the electrons on the largest shell.
Here's the orbital notation of Carbon: 1s^2 2s^2 2px^1 py^1
Carbon's largest shell is 2. Count the electrons on shell 2, and you get 4 valence electrons.
Orbital notation of Oxygen: 1s^2 2s^2 2px^2 py^1 pz^1
Oxygen's largest shell is 2. So, like with carbon, count the electrons on the largest shell. You get 6.
There is a way easier way of interpreting this where you do not even have to write the orbital notation. I wish I can explain, but just know the periods and the group numbers.